\(\mathrm{D = T - \frac{9}{25}(100 - H)}\)The formula above can be used to approximate the dew point D, in degrees...
GMAT Advanced Math : (Adv_Math) Questions
\(\mathrm{D = T - \frac{9}{25}(100 - H)}\)
The formula above can be used to approximate the dew point D, in degrees Fahrenheit, given the temperature T, in degrees Fahrenheit, and the relative humidity of H percent, where \(\mathrm{H \gt 50}\). Which of the following expresses the relative humidity in terms of the temperature and the dew point?
\(\mathrm{H = \frac{25}{9}(D - T) + 100}\)
\(\mathrm{H = \frac{25}{9}(D - T) - 100}\)
\(\mathrm{H = \frac{25}{9}(D + T) + 100}\)
\(\mathrm{H = \frac{25}{9}(D + T) - 100}\)
1. TRANSLATE the problem information
- Given formula: \(\mathrm{D = T - \frac{9}{25}(100 - H)}\)
- Goal: Express H in terms of D and T (solve for H)
2. INFER the approach
- We need to isolate H by systematically undoing the operations in the original equation
- Work backwards through the operations: subtraction, then multiplication by fraction
3. SIMPLIFY through algebraic manipulation
- Start: \(\mathrm{D = T - \frac{9}{25}(100 - H)}\)
- Subtract T from both sides: \(\mathrm{D - T = -\frac{9}{25}(100 - H)}\)
- Multiply both sides by -25/9: \(\mathrm{-\frac{25}{9}(D - T) = 100 - H}\)
- Subtract 100 from both sides: \(\mathrm{-\frac{25}{9}(D - T) - 100 = -H}\)
- Multiply both sides by -1: \(\mathrm{\frac{25}{9}(D - T) + 100 = H}\)
4. SIMPLIFY to final form
- \(\mathrm{H = \frac{25}{9}(D - T) + 100}\)
Answer: A
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak SIMPLIFY execution: Sign errors when multiplying by negative fractions
Students often lose track of negative signs, especially when multiplying both sides by -25/9. They might forget that multiplying by a negative flips signs, leading them to get 25/9(D - T) - 100 instead of 25/9(D - T) + 100.
This may lead them to select Choice B (\(\mathrm{H = \frac{25}{9}(D - T) - 100}\))
Second Most Common Error:
Poor SIMPLIFY reasoning: Incorrectly handling the (D - T) vs (D + T) terms
Some students make algebraic errors early in the process, particularly when moving T to the left side. Instead of getting D - T, they might incorrectly manipulate to get D + T, carrying this error through the remaining steps.
This may lead them to select Choice C (\(\mathrm{H = \frac{25}{9}(D + T) + 100}\)) or Choice D (\(\mathrm{H = \frac{25}{9}(D + T) - 100}\))
The Bottom Line:
This problem tests careful algebraic manipulation with attention to signs. The multiple negative operations create opportunities for sign errors that directly correspond to the incorrect answer choices.
\(\mathrm{H = \frac{25}{9}(D - T) + 100}\)
\(\mathrm{H = \frac{25}{9}(D - T) - 100}\)
\(\mathrm{H = \frac{25}{9}(D + T) + 100}\)
\(\mathrm{H = \frac{25}{9}(D + T) - 100}\)