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\(\mathrm{E(s) = -0.012s^2 + 1.2s + 15}\)The equation above models the fuel efficiency, E, in miles per gallon (mpg), of...

GMAT Advanced Math : (Adv_Math) Questions

Source: Prism
Advanced Math
Nonlinear functions
MEDIUM
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\(\mathrm{E(s) = -0.012s^2 + 1.2s + 15}\)

The equation above models the fuel efficiency, E, in miles per gallon (mpg), of a certain car at a constant speed of s miles per hour (mph), where \(\mathrm{20 \leq s \leq 75}\). Which of the following is the best interpretation of the ordered pair \(\mathrm{(50, 45)}\) in this context?

  1. The car's fuel efficiency is \(\mathrm{50}\) mpg when it travels at a speed of \(\mathrm{45}\) mph.
  2. The car's fuel efficiency increases by \(\mathrm{45}\) mpg for every \(\mathrm{50}\) mph increase in speed.
  3. When traveling \(\mathrm{50}\) miles, the car uses \(\mathrm{45}\) gallons of fuel.
  4. The car's fuel efficiency is \(\mathrm{45}\) mpg when it travels at a speed of \(\mathrm{50}\) mph.
A
The car's fuel efficiency is \(\mathrm{50\text{ mpg}}\) when it travels at a speed of \(\mathrm{45\text{ mph}}\).
B
The car's fuel efficiency increases by \(\mathrm{45\text{ mpg}}\) for every \(\mathrm{50\text{ mph}}\) increase in speed.
C
When traveling \(\mathrm{50\text{ miles}}\), the car uses \(\mathrm{45\text{ gallons}}\) of fuel.
D
The car's fuel efficiency is \(\mathrm{45\text{ mpg}}\) when it travels at a speed of \(\mathrm{50\text{ mph}}\).
Solution

1. TRANSLATE the function notation

  • Given: \(\mathrm{E(s) = -0.012s^2 + 1.2s + 15}\)
  • This means E (fuel efficiency in mpg) is a function of s (speed in mph)
  • Since it's written as E(s), ordered pairs follow the pattern (s, E)

2. TRANSLATE the ordered pair in context

  • The ordered pair \(\mathrm{(50, 45)}\) means:
    • First coordinate: s = 50 mph (speed)
    • Second coordinate: E = 45 mpg (fuel efficiency)
  • In words: "When speed is 50 mph, fuel efficiency is 45 mpg"

3. INFER which answer choice matches this interpretation

  • We need the choice that says efficiency is 45 mpg when speed is 50 mph
  • This matches exactly with choice (D)

4. Verify by substitution (optional)

  • \(\mathrm{E(50) = -0.012(50)^2 + 1.2(50) + 15 = 45}\)

Answer: D




Why Students Usually Falter on This Problem

Most Common Error Path:

Weak TRANSLATE skill: Students incorrectly assume ordered pairs are written as (E, s) instead of (s, E)

They see \(\mathrm{(50, 45)}\) and think "efficiency is 50 mpg when speed is 45 mph" because they're not paying attention to the function notation E(s). The function notation tells us that s is the input and E is the output, so ordered pairs must be \(\mathrm{(input, output) = (s, E)}\).

This leads them to select Choice A (The car's fuel efficiency is 50 mpg when it travels at a speed of 45 mph).

Second Most Common Error:

Conceptual confusion about function interpretation: Students misinterpret the single ordered pair as representing a rate of change rather than a specific point.

They see \(\mathrm{(50, 45)}\) and think it means "for every 50 mph increase in speed, efficiency increases by 45 mpg" instead of recognizing it as one specific input-output pair on the function.

This may lead them to select Choice B or causes confusion leading to guessing.

The Bottom Line:

Success on this problem requires careful attention to function notation - the way a function is written (E(s)) determines the order of coordinates in its ordered pairs.

Answer Choices Explained
A
The car's fuel efficiency is \(\mathrm{50\text{ mpg}}\) when it travels at a speed of \(\mathrm{45\text{ mph}}\).
B
The car's fuel efficiency increases by \(\mathrm{45\text{ mpg}}\) for every \(\mathrm{50\text{ mph}}\) increase in speed.
C
When traveling \(\mathrm{50\text{ miles}}\), the car uses \(\mathrm{45\text{ gallons}}\) of fuel.
D
The car's fuel efficiency is \(\mathrm{45\text{ mpg}}\) when it travels at a speed of \(\mathrm{50\text{ mph}}\).
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