An economist modeled the demand Q for a certain product as a linear function of the selling price P. The...
GMAT Algebra : (Alg) Questions
An economist modeled the demand \(\mathrm{Q}\) for a certain product as a linear function of the selling price \(\mathrm{P}\). The demand was \(20,000\) units when the selling price was \(\$40\) per unit, and the demand was \(15,000\) units when the selling price was \(\$60\) per unit. Based on the model, what is the demand, in units, when the selling price is \(\$55\) per unit?
1. TRANSLATE the problem information
- Given information:
- When price \(\mathrm{P = \$40}\), demand \(\mathrm{Q = 20{,}000}\) units → coordinate point \(\mathrm{(40, 20000)}\)
- When price \(\mathrm{P = \$60}\), demand \(\mathrm{Q = 15{,}000}\) units → coordinate point \(\mathrm{(60, 15000)}\)
- Need to find Q when \(\mathrm{P = \$55}\)
2. INFER the solution approach
- Since this is a linear function, I need to find the equation \(\mathrm{Q = mP + b}\)
- Strategy: Use the two points to find slope m, then find the y-intercept b
- Once I have the equation, substitute \(\mathrm{P = 55}\)
3. SIMPLIFY to find the slope
- Using slope formula: \(\mathrm{m = \frac{Q_2 - Q_1}{P_2 - P_1}}\)
- \(\mathrm{m = \frac{15000 - 20000}{60 - 40}}\)
\(\mathrm{= \frac{-5000}{20}}\)
\(\mathrm{= -250}\)
4. SIMPLIFY to find the complete equation
- Using point-slope form with \(\mathrm{(40, 20000)}\):
- \(\mathrm{Q - 20000 = -250(P - 40)}\)
- \(\mathrm{Q - 20000 = -250P + 10000}\)
- \(\mathrm{Q = -250P + 30000}\)
5. SIMPLIFY to find the final answer
- Substitute \(\mathrm{P = 55}\):
\(\mathrm{Q = -250(55) + 30000}\) - \(\mathrm{Q = -13750 + 30000}\)
\(\mathrm{= 16250}\)
Answer: A. 16,250
Why Students Usually Falter on This Problem
Most Common Error Path:
Poor TRANSLATE reasoning: Students mix up which variable goes with which coordinate, setting up points as \(\mathrm{(Q, P)}\) instead of \(\mathrm{(P, Q)}\). This leads to calculating slope as \(\mathrm{\frac{60 - 40}{15000 - 20000} = \frac{20}{-5000} = -0.004}\), which produces completely wrong equations and final answers that don't match any choice. This leads to confusion and guessing.
Second Most Common Error:
Weak SIMPLIFY execution: Students make sign errors when working with the negative slope, particularly when distributing \(\mathrm{-250(P - 40)}\) or when performing the final arithmetic. For example, calculating \(\mathrm{-250(55)}\) as \(\mathrm{+13750}\) instead of \(\mathrm{-13750}\), which gives \(\mathrm{Q = 13750 + 30000 = 43750}\). This leads to an answer far outside the given choices and causes them to get stuck and randomly select an answer.
The Bottom Line:
This problem tests whether students can systematically work with linear functions in a real-world context, requiring careful coordinate setup and consistent algebraic manipulation with negative slopes.