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\(\mathrm{a(3 - x) - b = -1 - 2x}\)In the equation above, a and b are constants. If the equation...

GMAT Algebra : (Alg) Questions

Source: Official
Algebra
Linear equations in 1 variable
MEDIUM
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Notes
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\(\mathrm{a(3 - x) - b = -1 - 2x}\)

In the equation above, a and b are constants. If the equation has infinitely many solutions, what are the values of a and b?

A
\(\mathrm{a = 2}\) and \(\mathrm{b = 1}\)
B
\(\mathrm{a = 2}\) and \(\mathrm{b = 7}\)
C
\(\mathrm{a = -2}\) and \(\mathrm{b = 5}\)
D
\(\mathrm{a = -2}\) and \(\mathrm{b = -5}\)
Solution

1. TRANSLATE the problem information

  • Given equation: \(\mathrm{a(3 - x) - b = -1 - 2x}\)
  • We need values of constants a and b that make this equation have infinitely many solutions

2. INFER what "infinitely many solutions" means

  • An equation has infinitely many solutions when it's an identity
  • This happens when both sides are exactly the same after simplification
  • The coefficients of like terms must be equal on both sides

3. SIMPLIFY by expanding the left side

  • Distribute the a: \(\mathrm{a(3 - x) - b = 3a - ax - b}\)
  • Our equation becomes: \(\mathrm{3a - ax - b = -1 - 2x}\)

4. SIMPLIFY by rearranging to group like terms

  • Move x-terms and constants together: \(\mathrm{-ax + 3a - b = -2x - 1}\)
  • Now we can compare coefficients directly

5. INFER the required relationships

  • For the equation to be an identity:
    • Coefficient of x on left = Coefficient of x on right
    • Constant term on left = Constant term on right

6. SIMPLIFY to find the values

  • Coefficients of x: \(\mathrm{-a = -2}\), so \(\mathrm{a = 2}\)
  • Constant terms: \(\mathrm{3a - b = -1}\)
  • Substitute \(\mathrm{a = 2}\): \(\mathrm{3(2) - b = -1}\)
  • Solve: \(\mathrm{6 - b = -1}\), so \(\mathrm{b = 7}\)

Answer: B. a = 2 and b = 7




Why Students Usually Falter on This Problem

Most Common Error Path:

Weak INFER skill: Students don't recognize what "infinitely many solutions" means mathematically. They might try to solve for specific values of x instead of understanding that the equation must be an identity. This leads to confusion and guessing among the answer choices.

Second Most Common Error:

Poor SIMPLIFY execution: Students make sign errors when distributing or rearranging terms. For example, they might get the wrong sign for the coefficient of x (writing \(\mathrm{+a = -2}\) instead of \(\mathrm{-a = -2}\)) or make errors in the constant terms. This may lead them to select Choice A (a = 2, b = 1) or Choice C (a = -2, b = 5).

The Bottom Line:

This problem tests whether students understand the deeper meaning of "infinitely many solutions" - it's not about finding x-values, but about making the equation an identity through proper coefficient matching.

Answer Choices Explained
A
\(\mathrm{a = 2}\) and \(\mathrm{b = 1}\)
B
\(\mathrm{a = 2}\) and \(\mathrm{b = 7}\)
C
\(\mathrm{a = -2}\) and \(\mathrm{b = 5}\)
D
\(\mathrm{a = -2}\) and \(\mathrm{b = -5}\)
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