\((\mathrm{x} + 2)(\mathrm{x} - 5)(\mathrm{x} + 9) = 0\)What is a positive solution to the given equation?
GMAT Advanced Math : (Adv_Math) Questions
\((\mathrm{x} + 2)(\mathrm{x} - 5)(\mathrm{x} + 9) = 0\)
What is a positive solution to the given equation?
\(3\)
\(4\)
\(5\)
\(18\)
1. INFER the solution strategy
- Given: \((\mathrm{x} + 2)(\mathrm{x} - 5)(\mathrm{x} + 9) = 0\)
- Key insight: When a product equals zero, at least one factor must be zero
- Strategy: Apply the zero product property by setting each factor equal to zero
2. SIMPLIFY by creating separate equations
Set each factor equal to zero:
- \(\mathrm{x} + 2 = 0\)
- \(\mathrm{x} - 5 = 0\)
- \(\mathrm{x} + 9 = 0\)
3. SIMPLIFY each linear equation
Solve systematically:
- From \(\mathrm{x} + 2 = 0\): Subtract 2 from both sides → \(\mathrm{x} = -2\)
- From \(\mathrm{x} - 5 = 0\): Add 5 to both sides → \(\mathrm{x} = 5\)
- From \(\mathrm{x} + 9 = 0\): Subtract 9 from both sides → \(\mathrm{x} = -9\)
4. APPLY CONSTRAINTS to select final answer
- All solutions: \(\mathrm{x} = -2, 5, -9\)
- Question asks for positive solution
- Since only \(5 \gt 0\), the positive solution is \(\mathrm{x} = 5\)
Answer: C. 5
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak INFER skill: Students don't recognize they can use the zero product property with the factored form. Instead, they might try to expand \((\mathrm{x} + 2)(\mathrm{x} - 5)(\mathrm{x} + 9)\) first, creating a cubic equation that's much harder to solve. This leads to confusion and potentially guessing among the answer choices.
Second Most Common Error:
Poor SIMPLIFY execution: Students apply zero product property correctly but make arithmetic errors when solving the linear equations. For example, from \(\mathrm{x} + 2 = 0\), they might incorrectly get \(\mathrm{x} = 2\) instead of \(\mathrm{x} = -2\). This could lead them to think 2 is a positive solution, but since 2 isn't among the choices, this causes confusion and guessing.
The Bottom Line:
This problem tests whether students can recognize when to use the zero product property rather than expanding. The factored form is a gift - use it! The real challenge is strategic recognition, not complex calculations.
\(3\)
\(4\)
\(5\)
\(18\)