prismlearning.academy Logo
NEUR
N

An event offered two time slots, morning and afternoon. A city report states that 60% of attendees chose the afternoon...

GMAT Algebra : (Alg) Questions

Source: Prism
Algebra
Systems of 2 linear equations in 2 variables
MEDIUM
...
...
Notes
Post a Query

An event offered two time slots, morning and afternoon. A city report states that \(60\%\) of attendees chose the afternoon slot. A ticketing summary states that \(180\) more attendees chose the afternoon slot than the morning slot. Based on these data, how many attendees chose the morning slot?

A

\(\mathrm{180}\)

B

\(\mathrm{270}\)

C

\(\mathrm{360}\)

D

\(\mathrm{540}\)

Solution

1. TRANSLATE the problem information

  • Given information:
    • 60% chose afternoon slot
    • Afternoon attendees exceed morning attendees by 180
  • What this tells us:
    • Morning attendees = 40% (since \(60\% + 40\% = 100\%\))
    • We need the actual number who chose morning

2. INFER the approach

  • Key insight: The difference between 60% and 40% is 20% of total attendees
  • Strategy: Use the fact that this 20% difference equals 180 people
  • Set up equation: \(0.60\mathrm{T} - 0.40\mathrm{T} = 180\), where T = total attendees

3. SIMPLIFY to find total attendees

  • \(0.60\mathrm{T} - 0.40\mathrm{T} = 180\)
  • \(0.20\mathrm{T} = 180\)
  • \(\mathrm{T} = 180 \div 0.20 = 900\) (use calculator)

4. Calculate morning attendees

  • Morning = 40% of total = \(0.40 \times 900 = 360\) (use calculator)

Answer: C (360)



Why Students Usually Falter on This Problem

Most Common Error Path:

Weak TRANSLATE skill: Students misinterpret what the problem is asking for and confuse the difference (180) with the final answer.

They might think: "180 more chose afternoon, so 180 chose morning." This completely ignores the percentage information and leads them to select Choice A (180).

Second Most Common Error:

Poor INFER reasoning: Students correctly set up the percentage relationships but incorrectly calculate which group to find.

They find the total (900) and then calculate afternoon attendees: \(0.60 \times 900 = 540\), leading them to select Choice D (540) instead of recognizing they need the morning count.

The Bottom Line:

This problem requires connecting percentage relationships with absolute differences - students must recognize that the percentage gap corresponds to the numerical gap, then work backwards to find the specific group requested.

Answer Choices Explained
A

\(\mathrm{180}\)

B

\(\mathrm{270}\)

C

\(\mathrm{360}\)

D

\(\mathrm{540}\)

Rate this Solution
Tell us what you think about this solution
...
...
Forum Discussions
Start a new discussion
Post
Load More
Similar Questions
Finding similar questions...
Previous Attempts
Loading attempts...
Similar Questions
Finding similar questions...
Parallel Question Generator
Create AI-generated questions with similar patterns to master this question type.