Question:The exponential function h is defined by \(\mathrm{h(x) = 12 \cdot b^x}\), where b is a positive constant. If \(\mathrm{h(2)...
GMAT Advanced Math : (Adv_Math) Questions
The exponential function h is defined by \(\mathrm{h(x) = 12 \cdot b^x}\), where \(\mathrm{b}\) is a positive constant. If \(\mathrm{h(2) = 48}\), what is the value of \(\mathrm{h(3)}\)?
1. TRANSLATE the given information into a solvable equation
- Given information:
- Function form: \(\mathrm{h(x) = 12 \cdot b^x}\)
- Known point: \(\mathrm{h(2) = 48}\)
- \(\mathrm{b}\) is positive
- TRANSLATE this into: \(\mathrm{48 = 12 \cdot b^2}\)
2. INFER the solution strategy
- To find \(\mathrm{h(3)}\), we first need to determine what \(\mathrm{b}\) is
- Once we know \(\mathrm{b}\), we can substitute any \(\mathrm{x}\)-value into the complete function
3. SIMPLIFY to solve for b
- Start with: \(\mathrm{48 = 12 \cdot b^2}\)
- Divide both sides by 12: \(\mathrm{b^2 = 4}\)
- Take the square root: \(\mathrm{b = 2}\) (positive since \(\mathrm{b \gt 0}\))
4. INFER the complete function and calculate h(3)
- Now we know: \(\mathrm{h(x) = 12 \cdot 2^x}\)
- Substitute \(\mathrm{x = 3}\): \(\mathrm{h(3) = 12 \cdot 2^3}\)
- SIMPLIFY: \(\mathrm{h(3) = 12 \cdot 8 = 96}\)
Answer: 96
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak TRANSLATE skill: Students struggle to connect "\(\mathrm{h(2) = 48}\)" with the function definition to create the equation \(\mathrm{48 = 12 \cdot b^2}\). They might recognize that \(\mathrm{h(2)}\) means "substitute 2 for \(\mathrm{x}\)" but fail to set up the equation properly.
Without this crucial first step, they get stuck immediately and resort to guessing.
Second Most Common Error:
Poor SIMPLIFY execution: Students set up the problem correctly but make arithmetic errors. Common mistakes include:
- Calculating \(\mathrm{48 \div 12}\) incorrectly
- Forgetting that \(\mathrm{2^3 = 8}\) (not 6)
- Making errors in the final multiplication \(\mathrm{12 \times 8}\)
These arithmetic slips can lead to various incorrect answers that seem reasonable.
The Bottom Line:
This problem tests whether students can work backwards from a known point on an exponential function to determine the base, then use that base to find another point. The key insight is recognizing that finding the unknown parameter comes first.