Let \(\mathrm{f(x) = \frac{5}{6}x - 9}\) and \(\mathrm{g(x) = \frac{1}{3}x + 7}\). Which of the following expressions is equivalent to...
GMAT Advanced Math : (Adv_Math) Questions
Let \(\mathrm{f(x) = \frac{5}{6}x - 9}\) and \(\mathrm{g(x) = \frac{1}{3}x + 7}\). Which of the following expressions is equivalent to \(\mathrm{f(x) - g(x)}\)?
\(-\frac{1}{2}x - 2\)
\(\frac{4}{9}x - 16\)
\(\frac{1}{2}x - 16\)
\(\frac{1}{2}x - 2\)
1. TRANSLATE the problem information
- Given functions:
- \(\mathrm{f(x) = \frac{5}{6}x - 9}\)
- \(\mathrm{g(x) = \frac{1}{3}x + 7}\)
- Need to find: \(\mathrm{f(x) - g(x)}\)
2. TRANSLATE this into a computational expression
- Substitute the function definitions:
\(\mathrm{f(x) - g(x) = \frac{5}{6}x - 9 - [(\frac{1}{3}x + 7)]}\)
3. SIMPLIFY by distributing the negative sign
- Apply the distributive property to remove brackets:
\(\mathrm{= \frac{5}{6}x - 9 - \frac{1}{3}x - 7}\) - The key is that the negative sign applies to both terms inside the brackets
4. SIMPLIFY by grouping and combining like terms
- Group x-terms and constants separately:
\(\mathrm{= \frac{5}{6}x - \frac{1}{3}x - 9 - 7}\)
- For x-terms, find common denominator:
\(\mathrm{\frac{5}{6} - \frac{1}{3} = \frac{5}{6} - \frac{2}{6} = \frac{3}{6} = \frac{1}{2}}\)
- For constants:
\(\mathrm{-9 - 7 = -16}\)
5. Write the final simplified form
- \(\mathrm{f(x) - g(x) = \frac{1}{2}x - 16}\)
Answer: C
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak SIMPLIFY skill: Making sign errors when distributing the negative through the parentheses
Students often write:
\(\mathrm{\frac{5}{6}x - 9 - \frac{1}{3}x + 7}\)
instead of
\(\mathrm{\frac{5}{6}x - 9 - \frac{1}{3}x - 7}\)
This gives them
\(\mathrm{-9 + 7 = -2}\)
for the constant term instead of
\(\mathrm{-9 - 7 = -16}\).
This may lead them to select Choice D (\(\mathrm{\frac{1}{2}x - 2}\))
The Bottom Line:
Function subtraction requires careful attention to sign management—the negative sign must be distributed to every term in the second function, not just the first term.
\(-\frac{1}{2}x - 2\)
\(\frac{4}{9}x - 16\)
\(\frac{1}{2}x - 16\)
\(\frac{1}{2}x - 2\)