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A farmers' market vendor charges a constant price per pound for peaches. The table shows the relationship between the weight...

GMAT Algebra : (Alg) Questions

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Algebra
Linear functions
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A farmers' market vendor charges a constant price per pound for peaches. The table shows the relationship between the weight \(\mathrm{w}\), in pounds, of peaches purchased and the total price \(\mathrm{P(w)}\), in dollars.

\(\mathrm{w}\)246
\(\mathrm{P(w)}\)7.5015.0022.50

Which equation could define P?

A

\(\mathrm{P(w) = 0.375w}\)

B

\(\mathrm{P(w) = 1.5w}\)

C

\(\mathrm{P(w) = 3.75w}\)

D

\(\mathrm{P(w) = 15w}\)

Solution

1. INFER the relationship type

  • Given information:
    • Constant price per pound for peaches
    • Table showing weight w and total price P(w)
  • What this tells us: Since the price per pound is constant, the total price is directly proportional to the weight. This means \(\mathrm{P(w) = k \cdot w}\), where k is the price per pound.

2. SIMPLIFY to find the constant of proportionality

  • Calculate the price per pound using any data point from the table:
    • Using (2 pounds, $7.50): Price per pound = \(\$7.50 \div 2 = \$3.75\)
  • This means \(\mathrm{k = 3.75}\), so our equation is \(\mathrm{P(w) = 3.75w}\)

3. INFER which answer choice matches

  • Looking at the choices:
    • (A) \(\mathrm{P(w) = 0.375w}\) → price per pound = $0.375
    • (B) \(\mathrm{P(w) = 1.5w}\) → price per pound = $1.50
    • (C) \(\mathrm{P(w) = 3.75w}\) → price per pound = $3.75 ✓
    • (D) \(\mathrm{P(w) = 15w}\) → price per pound = $15.00

4. Verify the answer

  • Check with other data points:
    • \(\mathrm{3.75 \times 4 = 15.00}\) ✓ (matches table)
    • \(\mathrm{3.75 \times 6 = 22.50}\) ✓ (matches table)

Answer: C




Why Students Usually Falter on This Problem

Most Common Error Path:

Weak INFER skill: Not recognizing the direct proportional relationship structure

Students might see the table and try to find patterns between consecutive values rather than understanding that "constant price per pound" means \(\mathrm{P(w) = (price\ per\ pound) \times w}\). They might calculate differences like \(\mathrm{15.00 - 7.50 = 7.50}\) or ratios between prices rather than recognizing they need price per unit weight.

This leads to confusion and guessing among the answer choices.


Second Most Common Error:

Poor SIMPLIFY execution: Calculating the wrong ratio

Students understand they need to find a rate but calculate incorrectly, such as:

  • Taking \(\mathrm{w \div P(w)}\) instead of \(\mathrm{P(w) \div w}\)
  • Using \(\mathrm{2 \div 7.50 = 0.267...}\) and selecting the closest value

This may lead them to select Choice A (0.375) since it's the only small decimal option.


The Bottom Line:

This problem tests whether students can translate the phrase "constant price per pound" into the mathematical concept of direct proportionality, then execute the unit rate calculation correctly.

Answer Choices Explained
A

\(\mathrm{P(w) = 0.375w}\)

B

\(\mathrm{P(w) = 1.5w}\)

C

\(\mathrm{P(w) = 3.75w}\)

D

\(\mathrm{P(w) = 15w}\)

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