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\(39\mathrm{x}^2 + (39\mathrm{a} + \mathrm{b})\mathrm{x} + \mathrm{ab} = 0\)In the given equation, a and b are positive constants. The sum...

GMAT Advanced Math : (Adv_Math) Questions

Source: Prism
Advanced Math
Nonlinear equations in 1 variable
HARD
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Notes
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\(39\mathrm{x}^2 + (39\mathrm{a} + \mathrm{b})\mathrm{x} + \mathrm{ab} = 0\)

In the given equation, a and b are positive constants. The sum of the solutions to the given equation is \(-(\mathrm{a} + \mathrm{kb})\), where \(\mathrm{k}\) is a constant. What is the value of \(\mathrm{k}\)?

A
\(\frac{1}{39}\)
B
\(\frac{1}{13}\)
C
\(1\)
D
\(39\)
Solution

1. TRANSLATE the problem information

  • Given equation: \(39\mathrm{x}^2 + (39\mathrm{a} + \mathrm{b})\mathrm{x} + \mathrm{ab} = 0\)
  • The sum of solutions equals \(-(\mathrm{a} + \mathrm{kb})\)
  • Need to find: the constant k

2. INFER the approach needed

  • This is asking for the sum of solutions of a quadratic equation
  • I need to use the sum of solutions formula: For \(\mathrm{Ax}^2 + \mathrm{Bx} + \mathrm{C} = 0\), \(\mathrm{sum} = -\mathrm{B}/\mathrm{A}\)
  • Then match this result with the given form \(-(\mathrm{a} + \mathrm{kb})\)

3. TRANSLATE the equation into standard form coefficients

  • Compare \(39\mathrm{x}^2 + (39\mathrm{a} + \mathrm{b})\mathrm{x} + \mathrm{ab} = 0\) with \(\mathrm{Ax}^2 + \mathrm{Bx} + \mathrm{C} = 0\)
  • \(\mathrm{A} = 39\)
  • \(\mathrm{B} = 39\mathrm{a} + \mathrm{b}\)
  • \(\mathrm{C} = \mathrm{ab}\)

4. SIMPLIFY using the sum formula

  • Sum of solutions \(= -\mathrm{B}/\mathrm{A}\)
  • \(= -(39\mathrm{a} + \mathrm{b})/39\)
  • Break apart the fraction:
  • \(-(39\mathrm{a} + \mathrm{b})/39 = -39\mathrm{a}/39 - \mathrm{b}/39\)
  • Simplify:
  • \(-39\mathrm{a}/39 - \mathrm{b}/39 = -\mathrm{a} - \mathrm{b}/39\)
  • \(= -(\mathrm{a} + \mathrm{b}/39)\)

5. INFER the value of k by comparison

  • We have: \(\mathrm{sum} = -(\mathrm{a} + \mathrm{b}/39)\)
  • Given form: \(\mathrm{sum} = -(\mathrm{a} + \mathrm{kb})\)
  • Setting equal: \(-(\mathrm{a} + \mathrm{b}/39) = -(\mathrm{a} + \mathrm{kb})\)
  • Therefore: \(\mathrm{b}/39 = \mathrm{kb}\)
  • Solving for k: \(\mathrm{k} = (\mathrm{b}/39)/\mathrm{b} = 1/39\)

Answer: A. 1/39


Why Students Usually Falter on This Problem

Most Common Error Path:

Weak TRANSLATE skill: Students don't recognize this as a sum of solutions problem, or they incorrectly identify the coefficients in the quadratic equation.

They might confuse which terms are A, B, and C, especially with the compound coefficient (39a + b) for the x term. This leads to using the wrong values in the sum formula and getting an incorrect expression for k.

This may lead them to select Choice C (1) if they mistakenly think k equals the ratio of the leading coefficients.

Second Most Common Error:

Poor SIMPLIFY execution: Students correctly apply the sum formula but make algebraic errors when separating \(-(39\mathrm{a} + \mathrm{b})/39\).

They might incorrectly simplify this as just \(-\mathrm{a} - \mathrm{b}\) instead of \(-\mathrm{a} - \mathrm{b}/39\), missing the crucial division of the b term by 39. This leads to comparing \(--(\mathrm{a} + \mathrm{b})\) with \(-(\mathrm{a} + \mathrm{kb})\), concluding that k = 1.

This leads them to select Choice C (1).

The Bottom Line:

This problem tests whether students can systematically apply the sum of solutions formula while carefully tracking algebraic manipulations involving compound expressions.

Answer Choices Explained
A
\(\frac{1}{39}\)
B
\(\frac{1}{13}\)
C
\(1\)
D
\(39\)
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