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The coordinate plane shows the graph of the linear equation \(\mathrm{y = 3g(x) + 6}\).The line passes through grid points...

GMAT Algebra : (Alg) Questions

Source: Prism
Algebra
Linear equations in 2 variables
HARD
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Notes
Post a Query

  1. The coordinate plane shows the graph of the linear equation \(\mathrm{y = 3g(x) + 6}\).
  2. The line passes through grid points that can be read from the graph.
  3. Which equation defines the function g?
A
\(\mathrm{g(x) = \frac{1}{2}x - 3}\)
B
\(\mathrm{g(x) = \frac{1}{2}x + 3}\)
C
\(\mathrm{g(x) = \frac{3}{2}x - 3}\)
D
\(\mathrm{g(x) = -\frac{1}{2}x - 3}\)
Solution

1. TRANSLATE the graph into mathematical information

  • TRANSLATE two clear points from the graphed line:
    • Point 1: Where the line crosses the y-axis at \(\mathrm{(0, -3)}\)
    • Point 2: Where the line crosses the x-axis at \(\mathrm{(2, 0)}\)

2. SIMPLIFY to find the equation of the graphed line

  • Calculate the slope:
    • \(\mathrm{\text{Slope} = \frac{0 - (-3)}{2 - 0} = \frac{3}{2}}\)
  • The y-intercept is -3 (from point \(\mathrm{(0, -3)}\))
  • Therefore, the graphed line has equation:
    • \(\mathrm{y} = \frac{3}{2}\mathrm{x} - 3\)

3. INFER the strategy to find g(x)

  • The key insight: The graph shows \(\mathrm{y} = 3\mathrm{g(x)} + 6\)
  • We found that the same graph represents \(\mathrm{y} = \frac{3}{2}\mathrm{x} - 3\)
  • These two expressions must be equal for all x
  • So we need to set them equal and solve for g(x)

4. SIMPLIFY through algebraic manipulation

  • Set the expressions equal:
    • \(3\mathrm{g(x)} + 6 = \frac{3}{2}\mathrm{x} - 3\)
  • Subtract 6 from both sides:
    • \(3\mathrm{g(x)} = \frac{3}{2}\mathrm{x} - 3 - 6\)
    • \(3\mathrm{g(x)} = \frac{3}{2}\mathrm{x} - 9\)
  • Divide everything by 3:
    • \(\mathrm{g(x)} = \frac{1}{2}\mathrm{x} - 3\)

5. Verify the answer

  • INFER that we should check our work by substituting back
  • If \(\mathrm{g(x)} = \frac{1}{2}\mathrm{x} - 3\), then:
    • \(3\mathrm{g(x)} + 6 = 3\left[\frac{1}{2}\mathrm{x} - 3\right] + 6\)
    • \(= \frac{3}{2}\mathrm{x} - 9 + 6\)
    • \(= \frac{3}{2}\mathrm{x} - 3\)

This matches our graphed equation!

Answer: A




Why Students Usually Falter on This Problem

Most Common Error Path:

Weak INFER skill: Not recognizing that the graphed line represents the transformed function y = 3g(x) + 6, not g(x) itself

Students see the equation \(\mathrm{y} = 3\mathrm{g(x)} + 6\) and might think they need to find an equation for the line shown and call that g(x). They correctly find that the graphed line is \(\mathrm{y} = \frac{3}{2}\mathrm{x} - 3\), but then mistakenly conclude that \(\mathrm{g(x)} = \frac{3}{2}\mathrm{x} - 3\).

This may lead them to select Choice (C): \(\mathrm{g(x)} = \frac{3}{2}\mathrm{x} - 3\)

Second Most Common Error:

Poor SIMPLIFY execution: Making sign errors when isolating g(x)

Students correctly set up \(3\mathrm{g(x)} + 6 = \frac{3}{2}\mathrm{x} - 3\), but then make errors in the algebra:

  • They might subtract 6 incorrectly: \(3\mathrm{g(x)} = \frac{3}{2}\mathrm{x} - 3 - 6\), but compute this as \(\frac{3}{2}\mathrm{x} + 3\) (forgetting that -3 - 6 = -9)
  • Then dividing by 3 gives: \(\mathrm{g(x)} = \frac{1}{2}\mathrm{x} + 1\), which they might round to match an answer

Or they might forget to subtract 6 and instead just divide the whole equation by 3 immediately, getting \(\mathrm{g(x)} + 2 = \frac{1}{2}\mathrm{x} - 1\), leading to \(\mathrm{g(x)} = \frac{1}{2}\mathrm{x} - 3 + 2 = \frac{1}{2}\mathrm{x} + 1\).

This confusion might lead them to select Choice (B): \(\mathrm{g(x)} = \frac{1}{2}\mathrm{x} + 3\) if they make additional sign errors.

The Bottom Line:

This problem requires students to understand the difference between a function and its transformation. The graph doesn't show g(x); it shows what happens to g(x) after it's been multiplied by 3 and increased by 6. Students must work backward algebraically to "undo" these transformations and find the original function g(x).

Answer Choices Explained
A
\(\mathrm{g(x) = \frac{1}{2}x - 3}\)
B
\(\mathrm{g(x) = \frac{1}{2}x + 3}\)
C
\(\mathrm{g(x) = \frac{3}{2}x - 3}\)
D
\(\mathrm{g(x) = -\frac{1}{2}x - 3}\)
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