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For the function g, the graph of \(\mathrm{y = g(x)}\) in the xy-plane has a slope of -{2} and passes...

GMAT Algebra : (Alg) Questions

Source: Prism
Algebra
Linear functions
EASY
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Notes
Post a Query

For the function \(\mathrm{g}\), the graph of \(\mathrm{y = g(x)}\) in the xy-plane has a slope of \(\mathrm{-2}\) and passes through the point \(\mathrm{(3, 1)}\). Which equation defines \(\mathrm{g}\)?

A
\(\mathrm{g(x) = -2x - 5}\)
B
\(\mathrm{g(x) = -2x + 1}\)
C
\(\mathrm{g(x) = -2x + 7}\)
D
\(\mathrm{g(x) = -2x + 9}\)
Solution

1. TRANSLATE the problem information

  • Given information:
    • \(\mathrm{Slope = -2}\)
    • Point on the line: \(\mathrm{(3, 1)}\)
    • Need to find: equation \(\mathrm{g(x)}\)

2. INFER the appropriate approach

  • Since we have a slope and one point, point-slope form is the most direct method
  • Point-slope form: \(\mathrm{y - y_1 = m(x - x_1)}\)
  • We'll convert this to slope-intercept form \(\mathrm{y = mx + b}\) to match the answer choices

3. SIMPLIFY using point-slope form

  • Substitute \(\mathrm{m = -2}\) and \(\mathrm{(x_1, y_1) = (3, 1)}\):
    \(\mathrm{y - 1 = -2(x - 3)}\)

4. SIMPLIFY through algebraic expansion

  • Distribute the -2:
    \(\mathrm{y - 1 = -2x + 6}\)
  • Add 1 to both sides:
    \(\mathrm{y = -2x + 6 + 1}\)
  • Combine constants:
    \(\mathrm{y = -2x + 7}\)

5. Express final answer

  • Therefore: \(\mathrm{g(x) = -2x + 7}\)

Answer: C




Why Students Usually Falter on This Problem

Most Common Error Path:

Weak SIMPLIFY skill: Students make sign errors when expanding \(\mathrm{-2(x - 3)}\)

Many students correctly set up \(\mathrm{y - 1 = -2(x - 3)}\), but then expand incorrectly as \(\mathrm{y - 1 = -2x - 6}\) instead of \(\mathrm{y - 1 = -2x + 6}\). This gives them \(\mathrm{y = -2x - 6 + 1 = -2x - 5}\).

This leads them to select Choice A (\(\mathrm{-2x - 5}\)).

Second Most Common Error:

Poor TRANSLATE reasoning: Students confuse point coordinates with slope-intercept components

Some students see the point \(\mathrm{(3, 1)}\) and incorrectly think the y-intercept is 1, immediately writing \(\mathrm{g(x) = -2x + 1}\) without using point-slope form.

This leads them to select Choice B (\(\mathrm{-2x + 1}\)).

The Bottom Line:

This problem tests whether students can systematically apply point-slope form and carefully handle negative signs during algebraic manipulation. The key is recognizing that having a slope and point means using point-slope form, not trying to directly identify slope-intercept components.

Answer Choices Explained
A
\(\mathrm{g(x) = -2x - 5}\)
B
\(\mathrm{g(x) = -2x + 1}\)
C
\(\mathrm{g(x) = -2x + 7}\)
D
\(\mathrm{g(x) = -2x + 9}\)
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