For the function g, the graph of \(\mathrm{y = g(x)}\) in the xy-plane has a slope of -{2} and passes...
GMAT Algebra : (Alg) Questions
For the function \(\mathrm{g}\), the graph of \(\mathrm{y = g(x)}\) in the xy-plane has a slope of \(\mathrm{-2}\) and passes through the point \(\mathrm{(3, 1)}\). Which equation defines \(\mathrm{g}\)?
1. TRANSLATE the problem information
- Given information:
- \(\mathrm{Slope = -2}\)
- Point on the line: \(\mathrm{(3, 1)}\)
- Need to find: equation \(\mathrm{g(x)}\)
2. INFER the appropriate approach
- Since we have a slope and one point, point-slope form is the most direct method
- Point-slope form: \(\mathrm{y - y_1 = m(x - x_1)}\)
- We'll convert this to slope-intercept form \(\mathrm{y = mx + b}\) to match the answer choices
3. SIMPLIFY using point-slope form
- Substitute \(\mathrm{m = -2}\) and \(\mathrm{(x_1, y_1) = (3, 1)}\):
\(\mathrm{y - 1 = -2(x - 3)}\)
4. SIMPLIFY through algebraic expansion
- Distribute the -2:
\(\mathrm{y - 1 = -2x + 6}\) - Add 1 to both sides:
\(\mathrm{y = -2x + 6 + 1}\) - Combine constants:
\(\mathrm{y = -2x + 7}\)
5. Express final answer
- Therefore: \(\mathrm{g(x) = -2x + 7}\)
Answer: C
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak SIMPLIFY skill: Students make sign errors when expanding \(\mathrm{-2(x - 3)}\)
Many students correctly set up \(\mathrm{y - 1 = -2(x - 3)}\), but then expand incorrectly as \(\mathrm{y - 1 = -2x - 6}\) instead of \(\mathrm{y - 1 = -2x + 6}\). This gives them \(\mathrm{y = -2x - 6 + 1 = -2x - 5}\).
This leads them to select Choice A (\(\mathrm{-2x - 5}\)).
Second Most Common Error:
Poor TRANSLATE reasoning: Students confuse point coordinates with slope-intercept components
Some students see the point \(\mathrm{(3, 1)}\) and incorrectly think the y-intercept is 1, immediately writing \(\mathrm{g(x) = -2x + 1}\) without using point-slope form.
This leads them to select Choice B (\(\mathrm{-2x + 1}\)).
The Bottom Line:
This problem tests whether students can systematically apply point-slope form and carefully handle negative signs during algebraic manipulation. The key is recognizing that having a slope and point means using point-slope form, not trying to directly identify slope-intercept components.