Let the function f be defined by \(\mathrm{f(x) = 3x^2 - 5x + 4}\), and let the function g be...
GMAT Advanced Math : (Adv_Math) Questions
Let the function f be defined by \(\mathrm{f(x) = 3x^2 - 5x + 4}\), and let the function g be defined by \(\mathrm{g(x) = 6x^2 + 20x - 13}\). Which expression is a factor of \(\mathrm{f(x) + g(x)}\)?
- 3
- 5
- 6
- \(\mathrm{3x}\)
\(\mathrm{3}\)
\(\mathrm{5}\)
\(\mathrm{6}\)
\(\mathrm{3x}\)
1. TRANSLATE the problem information
- Given functions:
- \(\mathrm{f(x) = 3x^2 - 5x + 4}\)
- \(\mathrm{g(x) = 6x^2 + 20x - 13}\)
- Need to find: A factor of \(\mathrm{f(x) + g(x)}\)
2. SIMPLIFY by adding the polynomials
- Add the two functions:
\(\mathrm{f(x) + g(x) = (3x^2 - 5x + 4) + (6x^2 + 20x - 13)}\)
- Combine like terms carefully:
- \(\mathrm{x^2}\) terms: \(\mathrm{3x^2 + 6x^2 = 9x^2}\)
- \(\mathrm{x}\) terms: \(\mathrm{-5x + 20x = 15x}\)
- Constants: \(\mathrm{4 + (-13) = -9}\)
- Result: \(\mathrm{f(x) + g(x) = 9x^2 + 15x - 9}\)
3. INFER the factoring strategy
- To find a factor, look for what divides all terms
- Check if coefficients 9, 15, and -9 have a common divisor
4. SIMPLIFY by finding the GCD
- Factor each coefficient:
- \(\mathrm{9 = 3 \times 3}\)
- \(\mathrm{15 = 3 \times 5}\)
- \(\mathrm{-9 = 3 \times (-3)}\)
- The GCD is 3 since it divides all coefficients
- Factor out 3: \(\mathrm{9x^2 + 15x - 9 = 3(3x^2 + 5x - 3)}\)
Answer: A (3)
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak SIMPLIFY skill: Making sign errors when combining like terms, especially with the constants \(\mathrm{4 + (-13)}\).
Students might calculate \(\mathrm{4 + (-13) = 17}\) instead of -9, or make errors with the x-coefficient \(\mathrm{(-5x + 20x)}\). This leads to an incorrect polynomial, making it impossible to identify the correct factor. This leads to confusion and guessing.
Second Most Common Error:
Missing INFER connection: Not recognizing that finding factors means looking for the GCD of coefficients.
Some students correctly find \(\mathrm{f(x) + g(x) = 9x^2 + 15x - 9}\) but then try to factor the entire quadratic expression rather than looking for common numerical factors. They might attempt to factor \(\mathrm{9x^2 + 15x - 9}\) as a product of binomials, which is more complex and unnecessary for this problem. This causes them to get stuck and guess.
The Bottom Line:
This problem tests whether students can systematically add polynomials and understand that finding "a factor" often means finding the simplest common factor of all terms, not necessarily factoring completely.
\(\mathrm{3}\)
\(\mathrm{5}\)
\(\mathrm{6}\)
\(\mathrm{3x}\)