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Let the function f be defined by \(\mathrm{f(x) = 3x^2 - 5x + 4}\), and let the function g be...

GMAT Advanced Math : (Adv_Math) Questions

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Advanced Math
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Let the function f be defined by \(\mathrm{f(x) = 3x^2 - 5x + 4}\), and let the function g be defined by \(\mathrm{g(x) = 6x^2 + 20x - 13}\). Which expression is a factor of \(\mathrm{f(x) + g(x)}\)?

  1. 3
  2. 5
  3. 6
  4. \(\mathrm{3x}\)
A

\(\mathrm{3}\)

B

\(\mathrm{5}\)

C

\(\mathrm{6}\)

D

\(\mathrm{3x}\)

Solution

1. TRANSLATE the problem information

  • Given functions:
    • \(\mathrm{f(x) = 3x^2 - 5x + 4}\)
    • \(\mathrm{g(x) = 6x^2 + 20x - 13}\)
  • Need to find: A factor of \(\mathrm{f(x) + g(x)}\)

2. SIMPLIFY by adding the polynomials

  • Add the two functions:
    \(\mathrm{f(x) + g(x) = (3x^2 - 5x + 4) + (6x^2 + 20x - 13)}\)
  • Combine like terms carefully:
    • \(\mathrm{x^2}\) terms: \(\mathrm{3x^2 + 6x^2 = 9x^2}\)
    • \(\mathrm{x}\) terms: \(\mathrm{-5x + 20x = 15x}\)
    • Constants: \(\mathrm{4 + (-13) = -9}\)
  • Result: \(\mathrm{f(x) + g(x) = 9x^2 + 15x - 9}\)

3. INFER the factoring strategy

  • To find a factor, look for what divides all terms
  • Check if coefficients 9, 15, and -9 have a common divisor

4. SIMPLIFY by finding the GCD

  • Factor each coefficient:
    • \(\mathrm{9 = 3 \times 3}\)
    • \(\mathrm{15 = 3 \times 5}\)
    • \(\mathrm{-9 = 3 \times (-3)}\)
  • The GCD is 3 since it divides all coefficients
  • Factor out 3: \(\mathrm{9x^2 + 15x - 9 = 3(3x^2 + 5x - 3)}\)

Answer: A (3)




Why Students Usually Falter on This Problem

Most Common Error Path:

Weak SIMPLIFY skill: Making sign errors when combining like terms, especially with the constants \(\mathrm{4 + (-13)}\).

Students might calculate \(\mathrm{4 + (-13) = 17}\) instead of -9, or make errors with the x-coefficient \(\mathrm{(-5x + 20x)}\). This leads to an incorrect polynomial, making it impossible to identify the correct factor. This leads to confusion and guessing.

Second Most Common Error:

Missing INFER connection: Not recognizing that finding factors means looking for the GCD of coefficients.

Some students correctly find \(\mathrm{f(x) + g(x) = 9x^2 + 15x - 9}\) but then try to factor the entire quadratic expression rather than looking for common numerical factors. They might attempt to factor \(\mathrm{9x^2 + 15x - 9}\) as a product of binomials, which is more complex and unnecessary for this problem. This causes them to get stuck and guess.

The Bottom Line:

This problem tests whether students can systematically add polynomials and understand that finding "a factor" often means finding the simplest common factor of all terms, not necessarily factoring completely.

Answer Choices Explained
A

\(\mathrm{3}\)

B

\(\mathrm{5}\)

C

\(\mathrm{6}\)

D

\(\mathrm{3x}\)

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