Function f is defined by \(\mathrm{f(x) = -a^x + b}\), where a and b are constants. In the xy-plane, the...
GMAT Advanced Math : (Adv_Math) Questions
Function f is defined by \(\mathrm{f(x) = -a^x + b}\), where a and b are constants. In the xy-plane, the graph of \(\mathrm{y = f(x) - 15}\) has a y-intercept at \(\mathrm{(0, -\frac{99}{7})}\). The product of a and b is \(\mathrm{\frac{65}{7}}\). What is the value of a?
1. TRANSLATE the problem information
- Given information:
- \(\mathrm{f(x) = -a^x + b}\) (exponential function)
- Graph of \(\mathrm{y = f(x) - 15}\) has y-intercept at \(\mathrm{(0, -99/7)}\)
- Product constraint: \(\mathrm{ab = 65/7}\)
- Need to find: value of a
2. TRANSLATE the y-intercept condition
- The graph \(\mathrm{y = f(x) - 15 = -a^x + b - 15}\) passes through \(\mathrm{(0, -99/7)}\)
- At \(\mathrm{x = 0}\): \(\mathrm{y = -a^0 + b - 15}\)
3. INFER the strategy
- Since \(\mathrm{a^0 = 1}\) for any nonzero a, we can find b first
- Then use the constraint \(\mathrm{ab = 65/7}\) to find a
4. SIMPLIFY to find b
- Substitute the y-intercept: \(\mathrm{-99/7 = -1 + b - 15}\)
- Combine constants: \(\mathrm{-99/7 = b - 16}\)
- Solve for b: \(\mathrm{b = -99/7 + 16 = -99/7 + 112/7 = 13/7}\)
5. SIMPLIFY using the product constraint
- From \(\mathrm{ab = 65/7}\) and \(\mathrm{b = 13/7}\):
- \(\mathrm{a(13/7) = 65/7}\)
- Divide both sides by 13/7: \(\mathrm{a = (65/7) ÷ (13/7) = 65/13 = 5}\)
Answer: 5
Why Students Usually Falter on This Problem
Most Common Error Path:
Conceptual confusion about exponential functions: Students might not remember that \(\mathrm{a^0 = 1}\), treating \(\mathrm{a^0}\) as 0 instead.
If they use \(\mathrm{a^0 = 0}\), they get:
\(\mathrm{-99/7 = 0 + b - 15 = b - 15}\)
So \(\mathrm{b = -99/7 + 15 = -99/7 + 105/7 = 6/7}\)
Then using \(\mathrm{ab = 65/7}\): \(\mathrm{a(6/7) = 65/7}\), giving \(\mathrm{a = 65/6 ≈ 10.83}\)
This leads to confusion since this isn't among typical answer choices, causing them to guess.
Second Most Common Error:
Poor SIMPLIFY execution with fraction arithmetic: Students make calculation errors when adding fractions or dividing by fractions.
For example, they might incorrectly calculate:
\(\mathrm{-99/7 + 16}\) as \(\mathrm{-99/23}\) instead of converting 16 to 112/7
This leads to wrong values for b and subsequently wrong values for a.
The Bottom Line:
This problem tests both conceptual knowledge of exponential functions (particularly \(\mathrm{a^0 = 1}\)) and careful algebraic manipulation with fractions. Success requires systematic work through the constraint equations rather than trying to work backwards from answer choices.