Question:If \(\mathrm{f(x) = ax + b}\) and \(\mathrm{f(2) = 11}\) and \(\mathrm{f(5) = 20}\), what is the value of \(\mathrm{f^{-1}(29)}\)?
GMAT Algebra : (Alg) Questions
If \(\mathrm{f(x) = ax + b}\) and \(\mathrm{f(2) = 11}\) and \(\mathrm{f(5) = 20}\), what is the value of \(\mathrm{f^{-1}(29)}\)?
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1. TRANSLATE the problem information
- Given information:
- \(\mathrm{f(x) = ax + b}\) (linear function with unknown coefficients)
- \(\mathrm{f(2) = 11}\) (when \(\mathrm{x = 2}\), the output is 11)
- \(\mathrm{f(5) = 20}\) (when \(\mathrm{x = 5}\), the output is 20)
- Find: \(\mathrm{f^{-1}(29)}\) (the input value that gives output 29)
2. INFER the approach
- To find \(\mathrm{f^{-1}(29)}\), we first need the explicit form of \(\mathrm{f(x)}\)
- This means finding the values of \(\mathrm{a}\) and \(\mathrm{b}\) using the given conditions
- Once we have \(\mathrm{f(x)}\), we can find its inverse function and evaluate it
3. SIMPLIFY to find the slope (coefficient a)
- Use the slope formula with points (2, 11) and (5, 20):
- \(\mathrm{a = \frac{20 - 11}{5 - 2}}\)
\(\mathrm{= \frac{9}{3}}\)
\(\mathrm{= 3}\)
- \(\mathrm{a = \frac{20 - 11}{5 - 2}}\)
4. SIMPLIFY to find the y-intercept (coefficient b)
- Substitute into \(\mathrm{f(2) = 11}\):
- \(\mathrm{11 = 3(2) + b}\)
\(\mathrm{11 = 6 + b}\)
\(\mathrm{b = 5}\)
- \(\mathrm{11 = 3(2) + b}\)
- Therefore: \(\mathrm{f(x) = 3x + 5}\)
5. INFER and SIMPLIFY to find the inverse function
- Start with \(\mathrm{y = 3x + 5}\)
- Solve for \(\mathrm{x}\) in terms of \(\mathrm{y}\):
- \(\mathrm{y - 5 = 3x}\)
\(\mathrm{x = \frac{y - 5}{3}}\)
- \(\mathrm{y - 5 = 3x}\)
- So \(\mathrm{f^{-1}(x) = \frac{x - 5}{3}}\)
6. SIMPLIFY the final calculation
- \(\mathrm{f^{-1}(29) = \frac{29 - 5}{3}}\)
\(\mathrm{= \frac{24}{3}}\)
\(\mathrm{= 8}\)
Answer: D (8)
Why Students Usually Falter on This Problem
Most Common Error Path:
Conceptual confusion about inverse notation: Students might interpret \(\mathrm{f^{-1}(29)}\) as \(\mathrm{\frac{1}{f(29)}}\) instead of the inverse function evaluated at 29.
Following this misconception, they would find \(\mathrm{f(29) = 3(29) + 5 = 92}\), then calculate \(\mathrm{\frac{1}{92} \approx 0.011}\), which doesn't match any answer choice. This leads to confusion and guessing.
Second Most Common Error:
Weak SIMPLIFY execution: Students correctly set up the system to find \(\mathrm{a}\) and \(\mathrm{b}\), but make arithmetic errors in the calculations or when manipulating the algebra to find the inverse function.
For example, they might incorrectly solve for \(\mathrm{b}\) and get \(\mathrm{f(x) = 3x + 2}\), leading to \(\mathrm{f^{-1}(x) = \frac{x - 2}{3}}\), giving \(\mathrm{f^{-1}(29) = \frac{27}{3} = 9}\). This may lead them to select Choice E (9).
The Bottom Line:
This problem tests whether students truly understand what an inverse function represents (undoing the original function) versus just applying reciprocal operations. The multi-step nature also requires careful algebraic manipulation throughout.
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