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The function g satisfies \(\mathrm{g(ax - 4) = 3x - 5}\) for all real numbers x, where a is a...

GMAT Algebra : (Alg) Questions

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Algebra
Linear functions
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The function \(\mathrm{g}\) satisfies \(\mathrm{g(ax - 4) = 3x - 5}\) for all real numbers \(\mathrm{x}\), where \(\mathrm{a}\) is a positive constant. It is also given that \(\mathrm{g(7) = 4}\). What is the value of \(\mathrm{a}\)?

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Solution

1. TRANSLATE the problem information

  • Given information:
    • \(\mathrm{g(ax - 4) = 3x - 5}\) for all real numbers x
    • a is a positive constant
    • \(\mathrm{g(7) = 4}\)
    • Need to find: value of a

2. INFER the solution strategy

  • The functional equation \(\mathrm{g(ax - 4) = 3x - 5}\) doesn't directly give us \(\mathrm{g(7)}\)
  • We need to transform this into standard function form \(\mathrm{g(y) = [expression\: in\: y]}\)
  • Key insight: Use substitution to eliminate the x-dependence

3. SIMPLIFY through substitution

  • Let \(\mathrm{y = ax - 4}\)
  • Solve for x: \(\mathrm{ax = y + 4}\), so \(\mathrm{x = \frac{y + 4}{a}}\)
  • Substitute back into \(\mathrm{g(ax - 4) = 3x - 5}\):
    \(\mathrm{g(y) = 3\left(\frac{y + 4}{a}\right) - 5}\)

4. SIMPLIFY the expression

  • Distribute: \(\mathrm{g(y) = \frac{3y + 12}{a} - 5}\)
  • Separate fractions: \(\mathrm{g(y) = \frac{3y}{a} + \frac{12}{a} - 5}\)
  • Now we have \(\mathrm{g(y)}\) in standard form!

5. INFER how to use the given condition

  • We know \(\mathrm{g(7) = 4}\), so substitute \(\mathrm{y = 7}\):
  • \(\mathrm{g(7) = \frac{3(7)}{a} + \frac{12}{a} - 5 = 4}\)

6. SIMPLIFY to solve for a

  • Combine like terms: \(\mathrm{\frac{21}{a} + \frac{12}{a} - 5 = 4}\)
  • Simplify: \(\mathrm{\frac{33}{a} - 5 = 4}\)
  • Add 5: \(\mathrm{\frac{33}{a} = 9}\)
  • Solve for a: \(\mathrm{a = \frac{33}{9} = \frac{11}{3}}\)

Answer: 11/3




Why Students Usually Falter on This Problem

Most Common Error Path:

Weak INFER skill: Students try to directly use \(\mathrm{g(7) = 4}\) without recognizing they need to transform the functional equation first. They might attempt to substitute \(\mathrm{x = 7}\) into \(\mathrm{g(ax - 4) = 3x - 5}\), getting \(\mathrm{g(7a - 4) = 3(7) - 5 = 16}\). But this gives them \(\mathrm{g(7a - 4) = 16}\), not \(\mathrm{g(7) = 4}\), leading to confusion about how to proceed. This causes them to get stuck and abandon systematic solution, often guessing randomly.


Second Most Common Error:

Poor SIMPLIFY execution: Students correctly set up the substitution but make algebraic errors when manipulating fractions. A common mistake is incorrectly distributing \(\mathrm{3\left(\frac{y + 4}{a}\right)}\), writing it as \(\mathrm{\frac{3y}{a} + \frac{4}{a}}\) instead of \(\mathrm{\frac{3y}{a} + \frac{12}{a}}\). This leads to \(\mathrm{g(7) = \frac{21}{a} + \frac{4}{a} - 5 = \frac{25}{a} - 5 = 4}\), giving \(\mathrm{\frac{25}{a} = 9}\), so \(\mathrm{a = \frac{25}{9}}\). Since \(\mathrm{\frac{25}{9}}\) isn't among typical answer choices, this creates confusion and guessing.


The Bottom Line:

This problem requires students to recognize that functional equations often need transformation before direct evaluation. The key insight is using substitution to convert the given form into standard function notation.

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The function g satisfies \(\mathrm{g(ax - 4) = 3x - 5}\) for all real numbers x, where a is a positive constant. It is also given that \(\mathrm{g(7) = 4}\). What is the value of a? : Algebra (Alg)