Let g be a function defined for all real numbers such that \(\mathrm{g(x + 1) = x^3 + 15}\). What...
GMAT Advanced Math : (Adv_Math) Questions
Let g be a function defined for all real numbers such that \(\mathrm{g(x + 1) = x^3 + 15}\). What is the value of \(\mathrm{g(3)}\)?
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1. TRANSLATE the problem information
- Given information: \(\mathrm{g(x + 1) = x^3 + 15}\)
- Need to find: \(\mathrm{g(3)}\)
- This means we need to find the output when the input to function g is 3
2. INFER the solution strategy
- The function is defined in terms of \(\mathrm{g(x + 1)}\), not \(\mathrm{g(x)}\)
- To find \(\mathrm{g(3)}\), we need to figure out what value of x makes \(\mathrm{x + 1 = 3}\)
- Key insight: Set up the equation \(\mathrm{x + 1 = 3}\)
3. SIMPLIFY to find the x-value
- Solve \(\mathrm{x + 1 = 3}\)
- Therefore \(\mathrm{x = 2}\)
4. SIMPLIFY to evaluate the function
- Now substitute \(\mathrm{x = 2}\) into the original function:
- \(\mathrm{g(3) = g(2 + 1) = 2^3 + 15}\)
- Calculate: \(\mathrm{2^3 = 8}\)
- Final calculation: \(\mathrm{8 + 15 = 23}\)
Answer: C. 23
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak INFER skill: Students don't recognize the substitution strategy and instead try to plug \(\mathrm{x = 3}\) directly into \(\mathrm{x^3 + 15}\).
They think: "I need \(\mathrm{g(3)}\), so I'll use \(\mathrm{x = 3}\)" and calculate \(\mathrm{3^3 + 15 = 27 + 15 = 42}\). When they don't see 42 among the choices, they might just pick \(\mathrm{3^3 = 27}\).
This may lead them to select Choice (E) (27).
Second Most Common Error:
Poor TRANSLATE reasoning: Students misunderstand what the functional notation means and get confused about which variable represents the input.
They might set \(\mathrm{g(3) = 3^3 + 15}\) directly, thinking that since we want \(\mathrm{g(3)}\), we substitute 3 for x everywhere.
This leads to confusion and potentially guessing among the available choices.
The Bottom Line:
The key challenge is recognizing that when a function is defined as \(\mathrm{g(x + 1)}\), finding \(\mathrm{g(3)}\) requires working backwards to determine what x-value makes \(\mathrm{x + 1 = 3}\). This substitution insight is what separates successful students from those who get stuck.
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