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The graph of \(\mathrm{y = f(x) + 14}\) is shown. Which equation defines function f?

GMAT Algebra : (Alg) Questions

Source: Official
Algebra
Linear equations in 2 variables
HARD
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The graph of \(\mathrm{y = f(x) + 14}\) is shown. Which equation defines function \(\mathrm{f}\)?


A
\(\mathrm{f(x) = -\frac{1}{4}x - 12}\)
B
\(\mathrm{f(x) = -\frac{1}{4}x + 16}\)
C
\(\mathrm{f(x) = -\frac{1}{4}x + 2}\)
D
\(\mathrm{f(x) = -\frac{1}{4}x - 14}\)
Solution

1. TRANSLATE the problem information

The problem states "The graph of \(\mathrm{y = f(x) + 14}\) is shown."

This is crucial: The line you see on the graph is NOT \(\mathrm{f(x)}\). It's \(\mathrm{f(x) + 14}\).

Think of it this way: Someone took the original function \(\mathrm{f(x)}\), added 14 to every output, and graphed the result. We need to work backwards to find the original function.

2. INFER the solution strategy

To find \(\mathrm{f(x)}\), we need to:

  • First, find the equation of the line shown in the graph
  • Then, use the relationship "line shown = \(\mathrm{f(x) + 14}\)" to solve for \(\mathrm{f(x)}\)

3. TRANSLATE information from the graph

Reading from the graph:

  • The y-intercept (where the line crosses the y-axis) is at \(\mathrm{(0, 2)}\)
  • The line also passes through \(\mathrm{(4, 1)}\)

4. Calculate the slope

Using the slope formula with points \(\mathrm{(0, 2)}\) and \(\mathrm{(4, 1)}\):

\(\mathrm{m = \frac{y_2 - y_1}{x_2 - x_1}}\)

\(\mathrm{= \frac{1 - 2}{4 - 0}}\)

\(\mathrm{= -\frac{1}{4}}\)

5. Write the equation of the line shown

Using slope-intercept form \(\mathrm{y = mx + b}\):

  • Slope \(\mathrm{m = -\frac{1}{4}}\)
  • Y-intercept \(\mathrm{b = 2}\)

The line shown has equation: \(\mathrm{y = -\frac{1}{4}x + 2}\)

6. Set up the relationship

We know the line shown represents \(\mathrm{y = f(x) + 14}\)

So: \(\mathrm{f(x) + 14 = -\frac{1}{4}x + 2}\)

7. SIMPLIFY to solve for f(x)

Subtract 14 from both sides:

\(\mathrm{f(x) = -\frac{1}{4}x + 2 - 14}\)

\(\mathrm{f(x) = -\frac{1}{4}x - 12}\)

Answer: A. \(\mathrm{f(x) = -\frac{1}{4}x - 12}\)




Why Students Usually Falter on This Problem

Most Common Error Path:

Weak TRANSLATE skill: Students misinterpret "the graph of \(\mathrm{y = f(x) + 14}\) is shown" and think the line displayed IS the function \(\mathrm{f(x)}\) itself.

When they find the equation of the line shown as \(\mathrm{y = -\frac{1}{4}x + 2}\), they incorrectly conclude that \(\mathrm{f(x) = -\frac{1}{4}x + 2}\).

This may lead them to select Choice C (\(\mathrm{f(x) = -\frac{1}{4}x + 2}\)).

Second Most Common Error:

Poor SIMPLIFY execution: Students correctly set up \(\mathrm{f(x) + 14 = -\frac{1}{4}x + 2}\) but make an arithmetic error when subtracting 14 from 2. Common mistakes include:

  • Computing \(\mathrm{2 - 14 = 16}\) (confusing subtraction with addition)
  • Computing \(\mathrm{2 - 14 = -16}\) (doubling the 14 instead of subtracting it)

These errors may lead them to select Choice B (\(\mathrm{f(x) = -\frac{1}{4}x + 16}\)) or Choice D (\(\mathrm{f(x) = -\frac{1}{4}x - 14}\)).

The Bottom Line:

This problem tests whether students can distinguish between a function and its transformation. The key challenge is understanding that when you're shown the graph of a transformed function, you must "undo" the transformation algebraically to find the original function. The "\(\mathrm{+14}\)" in the problem description means the graph has been shifted UP by 14 units, so to find the original, you must shift DOWN by 14 (subtract 14).

Answer Choices Explained
A
\(\mathrm{f(x) = -\frac{1}{4}x - 12}\)
B
\(\mathrm{f(x) = -\frac{1}{4}x + 16}\)
C
\(\mathrm{f(x) = -\frac{1}{4}x + 2}\)
D
\(\mathrm{f(x) = -\frac{1}{4}x - 14}\)
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