In the xy-plane, the graph of the given equation x^2 + 58x + y^2 = 0 is a circle. What...
GMAT Geometry & Trigonometry : (Geo_Trig) Questions
In the xy-plane, the graph of the given equation \(\mathrm{x^2 + 58x + y^2 = 0}\) is a circle. What are the coordinates \(\mathrm{(x, y)}\) of the center of the circle?
1. TRANSLATE the problem information
- Given equation: \(\mathrm{x^2 + 58x + y^2 = 0}\)
- Need to find: coordinates \(\mathrm{(x, y)}\) of the center
2. INFER the approach needed
- The equation isn't in standard circle form \(\mathrm{(x - h)^2 + (y - k)^2 = r^2}\)
- To find the center \(\mathrm{(h, k)}\), I need to complete the square
- Focus on the x terms since \(\mathrm{y^2}\) is already in perfect form
3. SIMPLIFY by completing the square
- For \(\mathrm{x^2 + 58x}\), I need to add and subtract \(\mathrm{(58/2)^2 = 29^2 = 841}\)
- Rewrite: \(\mathrm{x^2 + 58x + 841 - 841 + y^2 = 0}\)
- Group: \(\mathrm{(x^2 + 58x + 841) + y^2 = 841}\)
- Factor: \(\mathrm{(x + 29)^2 + y^2 = 841}\)
4. INFER the center coordinates
- Standard form is \(\mathrm{(x - h)^2 + (y - k)^2 = r^2}\)
- My equation: \(\mathrm{(x + 29)^2 + (y - 0)^2 = 841}\)
- This means: \(\mathrm{(x - (-29))^2 + (y - 0)^2 = 841}\)
- Therefore: \(\mathrm{h = -29}\) and \(\mathrm{k = 0}\)
Answer: D. \(\mathrm{(-29, 0)}\)
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak SIMPLIFY execution: Sign confusion during completing the square
Students correctly identify they need to complete the square but make a sign error. They might write \(\mathrm{(x - 29)^2}\) instead of \(\mathrm{(x + 29)^2}\), thinking the center x-coordinate is +29 instead of -29. Remember: \(\mathrm{(x + 29)^2 = (x - (-29))^2}\), so the center x-coordinate is -29.
This may lead them to select Choice C. \(\mathrm{(29, 0)}\)
Second Most Common Error:
Conceptual confusion about coordinate identification: Mixing up which number goes with which coordinate
Some students complete the square correctly but then confuse which coordinate is which. They might think the 29 (or -29) goes with the y-coordinate instead of the x-coordinate, since they see the 58 coefficient with x but don't clearly connect it to the final center coordinates.
This may lead them to select Choice A. \(\mathrm{(0, 29)}\) or Choice B. \(\mathrm{(0, -29)}\)
The Bottom Line:
The key challenge is executing completing the square accurately while keeping track of signs, then correctly interpreting what the standard form tells you about the center coordinates.