The function g is defined by \(\mathrm{g(x) = 5x + 45}\). At what point does the graph of \(\mathrm{y =...
GMAT Algebra : (Alg) Questions
The function \(\mathrm{g}\) is defined by \(\mathrm{g(x) = 5x + 45}\). At what point does the graph of \(\mathrm{y = g(x)}\) intersect the line \(\mathrm{y = 15}\) in the xy-plane?
\((-9, 0)\)
\((-6, 15)\)
\((-6, 0)\)
\((6, 15)\)
1. TRANSLATE the intersection requirement
- Given information:
- Function \(\mathrm{g(x) = 5x + 45}\)
- Need intersection with line \(\mathrm{y = 15}\)
- What this means: At the intersection point, both graphs have the same y-value, so g(x) must equal 15
2. TRANSLATE this into an equation
- Set the function equal to 15:
\(\mathrm{5x + 45 = 15}\)
3. SIMPLIFY to solve for x
- Subtract 45 from both sides:
\(\mathrm{5x = 15 - 45 = -30}\) - Divide both sides by 5:
\(\mathrm{x = -6}\)
4. INFER the complete intersection point
- Since we found \(\mathrm{x = -6}\) and we know the intersection occurs where \(\mathrm{y = 15}\)
- The intersection point is \(\mathrm{(-6, 15)}\)
Answer: B (-6, 15)
Why Students Usually Falter on This Problem
Most Common Error Path:
Incomplete INFER reasoning: Students solve correctly for \(\mathrm{x = -6}\) but then report the intersection point as \(\mathrm{(-6, 0)}\) instead of \(\mathrm{(-6, 15)}\).
This happens because they forget that the intersection is with the horizontal line \(\mathrm{y = 15}\), not with the x-axis. They correctly find where \(\mathrm{x = -6}\), but then assume the y-coordinate is 0 because they're thinking of x-intercepts rather than the specific line \(\mathrm{y = 15}\).
This leads them to select Choice C (-6, 0).
Second Most Common Error:
Weak SIMPLIFY execution: Students make arithmetic errors when solving \(\mathrm{5x + 45 = 15}\), particularly with the subtraction step.
A common mistake is: \(\mathrm{5x = 15 + 45 = 60}\), leading to \(\mathrm{x = 12}\). However, since 12 isn't among the x-coordinates in the choices, this typically leads to confusion and guessing rather than a specific wrong answer.
The Bottom Line:
This problem requires students to understand that "intersection with \(\mathrm{y = 15}\)" means finding where the function output equals 15, and then remembering that the intersection point includes both the x-value they calculated AND the y-value from the given horizontal line.
\((-9, 0)\)
\((-6, 15)\)
\((-6, 0)\)
\((6, 15)\)