For the function \(\mathrm{g(x) = x^3 + 2x^2 + kx - 3}\), where k is a constant, the graph of...
GMAT Advanced Math : (Adv_Math) Questions
For the function \(\mathrm{g(x) = x^3 + 2x^2 + kx - 3}\), where \(\mathrm{k}\) is a constant, the graph of \(\mathrm{y = g(x)}\) passes through the point \(\mathrm{(2, 21)}\). What is the value of \(\mathrm{k}\)?
1. TRANSLATE the point condition
- Given information:
- Function: \(\mathrm{g(x) = x^3 + 2x^2 + kx - 3}\)
- The graph passes through point \(\mathrm{(2, 21)}\)
- What this tells us: Since \(\mathrm{(2, 21)}\) is on the graph, when we input \(\mathrm{x = 2}\), we must get output \(\mathrm{y = 21}\). Therefore: \(\mathrm{g(2) = 21}\)
2. SIMPLIFY by substituting x = 2
- Substitute \(\mathrm{x = 2}\) into the function:
\(\mathrm{g(2) = (2)^3 + 2(2)^2 + k(2) - 3}\)
- Evaluate the powers and products:
\(\mathrm{g(2) = 8 + 2(4) + 2k - 3}\)
\(\mathrm{g(2) = 8 + 8 + 2k - 3}\)
\(\mathrm{g(2) = 13 + 2k}\)
3. SIMPLIFY by solving the equation
- Since \(\mathrm{g(2) = 21}\), we have:
\(\mathrm{13 + 2k = 21}\)
- Subtract 13 from both sides:
\(\mathrm{2k = 8}\)
- Divide by 2:
\(\mathrm{k = 4}\)
Answer: 4
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak TRANSLATE skill: Students don't connect "passes through \(\mathrm{(2, 21)}\)" to the condition \(\mathrm{g(2) = 21}\). They might try to substitute the point coordinates incorrectly, like setting \(\mathrm{x^3 + 2x^2 + kx - 3 = 2 + 21}\), or they might not know how to use the point information at all. This leads to confusion and guessing.
Second Most Common Error:
Poor SIMPLIFY execution: Students make arithmetic errors when evaluating the polynomial. Common mistakes include computing \(\mathrm{(2)^3}\) as 6 instead of 8, or \(\mathrm{2(2)^2}\) as 6 instead of 8, leading to incorrect expressions like \(\mathrm{11 + 2k = 21}\), which gives \(\mathrm{k = 5}\). This may lead them to select an incorrect answer.
The Bottom Line:
This problem tests whether students understand the fundamental relationship between points on a graph and function values. The key insight is recognizing that geometric information (a point on the graph) translates directly to algebraic information (an equation to solve).