The function h is defined by \(\mathrm{h(x) = k \cdot x^{3/2}}\), where k is a positive constant. If \(\mathrm{h(4) =...
GMAT Advanced Math : (Adv_Math) Questions
Source: Prism
Advanced Math
Nonlinear functions
MEDIUM
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Notes
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The function h is defined by \(\mathrm{h(x) = k \cdot x^{3/2}}\), where k is a positive constant. If \(\mathrm{h(4) = 96}\), what is the value of \(\mathrm{h(9)}\)?
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Solution
1. TRANSLATE the problem information
- Given information:
- \(\mathrm{h(x) = k \cdot x^{3/2}}\) where \(\mathrm{k}\) is a positive constant
- \(\mathrm{h(4) = 96}\)
- What this tells us: We can use the known value \(\mathrm{h(4) = 96}\) to find \(\mathrm{k}\), then use \(\mathrm{k}\) to calculate \(\mathrm{h(9)}\)
2. TRANSLATE the given condition into an equation
- Since \(\mathrm{h(4) = 96}\) and \(\mathrm{h(x) = k \cdot x^{3/2}}\):
\(\mathrm{k \cdot 4^{3/2} = 96}\)
3. SIMPLIFY to find the constant k
- Calculate \(\mathrm{4^{3/2}}\):
\(\mathrm{4^{3/2} = (4^{1/2})^3}\)
\(\mathrm{= (\sqrt{4})^3}\)
\(\mathrm{= 2^3}\)
\(\mathrm{= 8}\) - Substitute back: \(\mathrm{k \cdot 8 = 96}\)
- Solve for \(\mathrm{k}\): \(\mathrm{k = 96 \div 8 = 12}\)
4. SIMPLIFY to find h(9)
- Now we know \(\mathrm{k = 12}\), so: \(\mathrm{h(9) = 12 \cdot 9^{3/2}}\)
- Calculate \(\mathrm{9^{3/2}}\):
\(\mathrm{9^{3/2} = (9^{1/2})^3}\)
\(\mathrm{= (\sqrt{9})^3}\)
\(\mathrm{= 3^3}\)
\(\mathrm{= 27}\) - Final calculation: \(\mathrm{h(9) = 12 \cdot 27 = 324}\)
Answer: D) 324
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak SIMPLIFY skill: Misunderstanding fractional exponents
Many students incorrectly interpret \(\mathrm{x^{3/2}}\) as "3 divided by 2 times x" or confuse it with other operations. For example, they might calculate:
- \(\mathrm{4^{3/2}}\) as \(\mathrm{4 \times (3/2) = 6}\), leading to \(\mathrm{k = 96 \div 6 = 16}\)
- Then \(\mathrm{h(9) = 16 \times 6 = 96}\), which isn't among the answer choices
This leads to confusion and guessing.
Second Most Common Error:
Incomplete SIMPLIFY execution: Correct method but calculation errors
Students understand that \(\mathrm{4^{3/2} = (\sqrt{4})^3}\) but make arithmetic mistakes:
- Calculate \(\mathrm{(\sqrt{4})^3 = 2^2 = 4}\) instead of \(\mathrm{2^3 = 8}\)
- This gives \(\mathrm{k = 96 \div 4 = 24}\)
- Then \(\mathrm{h(9) = 24 \times 27 = 648}\), which is far from any answer choice
This causes them to get stuck and guess among the provided options.
The Bottom Line:
Success on this problem hinges on correctly handling fractional exponents. The key insight is recognizing that \(\mathrm{x^{3/2}}\) means "take the square root, then cube the result" - a two-step process that many students rush through or misunderstand.
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