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Which expression is equivalent to h^(16) q^(7)/h^(2) q^(21), where h gt 0 and q gt 0?

GMAT Advanced Math : (Adv_Math) Questions

Source: Practice Test
Advanced Math
Equivalent expressions
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Which expression is equivalent to \(\frac{\mathrm{h}^{16} \mathrm{q}^{7}}{\mathrm{h}^{2} \mathrm{q}^{21}}\), where \(\mathrm{h} \gt 0\) and \(\mathrm{q} \gt 0\)?

A
\(\frac{\mathrm{h}^{10}}{\mathrm{q}^{14}}\)
B
\(\frac{\mathrm{h}^{8}}{\mathrm{q}^{3}}\)
C
\(\mathrm{h}^{10}\mathrm{q}^{14}\)
D
\(\mathrm{h}^{8}\mathrm{q}^{3}\)
Solution

1. TRANSLATE the problem information

  • Given: \(\frac{\mathrm{h}^{16} \mathrm{q}^{7}}{\mathrm{h}^{2} \mathrm{q}^{21}}\) where \(\mathrm{h} \gt 0\) and \(\mathrm{q} \gt 0\)
  • Find: Equivalent simplified expression

2. INFER the approach

  • Since we have the same bases in numerator and denominator, use quotient rule for exponents
  • Apply the rule separately to each variable: h and q
  • Handle any negative exponents that result

3. SIMPLIFY using quotient rule for exponents

  • For h terms: \(\frac{\mathrm{h}^{16}}{\mathrm{h}^{2}} = \mathrm{h}^{16-2} = \mathrm{h}^{10}\)
  • For q terms: \(\frac{\mathrm{q}^{7}}{\mathrm{q}^{21}} = \mathrm{q}^{7-21} = \mathrm{q}^{-14}\)
  • Combined result: \(\mathrm{h}^{10} \times \mathrm{q}^{-14}\)

4. SIMPLIFY the negative exponent

  • Since \(\mathrm{q}^{-14} = \frac{1}{\mathrm{q}^{14}}\)
  • The expression becomes: \(\mathrm{h}^{10} \times \frac{1}{\mathrm{q}^{14}} = \frac{\mathrm{h}^{10}}{\mathrm{q}^{14}}\)

Answer: A. \(\frac{\mathrm{h}^{10}}{\mathrm{q}^{14}}\)




Why Students Usually Falter on This Problem

Most Common Error Path:

Weak SIMPLIFY skill: Students make arithmetic errors when subtracting exponents, particularly with the q terms where \(7-21 = -14\). Some students might calculate this as \(21-7 = 14\) instead, leading to \(\mathrm{q}^{14}\) in the numerator rather than \(\mathrm{q}^{-14} = \frac{1}{\mathrm{q}^{14}}\) in the denominator.

This may lead them to select Choice C (\(\mathrm{h}^{10} \mathrm{q}^{14}\)).

Second Most Common Error:

Conceptual confusion about negative exponents: Students correctly subtract exponents but don't remember that negative exponents create reciprocals. They might leave \(\mathrm{q}^{-14}\) as is or mishandle the conversion.

This leads to confusion and guessing between the remaining choices.

The Bottom Line:

This problem tests two fundamental exponent rules in sequence - students must both apply the quotient rule correctly AND properly handle the negative exponent that results. Missing either step leads to an incorrect answer.

Answer Choices Explained
A
\(\frac{\mathrm{h}^{10}}{\mathrm{q}^{14}}\)
B
\(\frac{\mathrm{h}^{8}}{\mathrm{q}^{3}}\)
C
\(\mathrm{h}^{10}\mathrm{q}^{14}\)
D
\(\mathrm{h}^{8}\mathrm{q}^{3}\)
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