Question:A home repair service uses a pricing structure with a flat fee plus an hourly rate. The service charges a...
GMAT Algebra : (Alg) Questions
A home repair service uses a pricing structure with a flat fee plus an hourly rate. The service charges a flat fee of \(\mathrm{b}\) dollars and a constant hourly rate of \(\mathrm{m}\) dollars per hour. For any job, the hourly rate is twice the flat fee, and a 5-hour job costs 44 dollars. What is the total cost, in dollars, of a 10-hour job?
1. TRANSLATE the problem information
- Given information:
- Flat fee: \(\mathrm{b}\) dollars
- Hourly rate: \(\mathrm{m}\) dollars per hour
- Hourly rate is twice the flat fee: \(\mathrm{m = 2b}\)
- A 5-hour job costs $44
- Need: cost of 10-hour job
- What this tells us: We have a linear cost function \(\mathrm{C(h) = mh + b}\) with a constraint relating \(\mathrm{m}\) and \(\mathrm{b}\)
2. INFER the approach
- Since we have one equation with two unknowns (\(\mathrm{m}\) and \(\mathrm{b}\)), we need to use the constraint \(\mathrm{m = 2b}\) to eliminate one variable
- We'll substitute this constraint into our cost equation for the 5-hour job to solve for \(\mathrm{b}\) first
- Once we find \(\mathrm{b}\), we can find \(\mathrm{m}\), then calculate the 10-hour cost
3. Set up the equation for the 5-hour job
- \(\mathrm{C(5) = m(5) + b = 44}\)
- This gives us: \(\mathrm{5m + b = 44}\)
4. SIMPLIFY using substitution
- Substitute \(\mathrm{m = 2b}\) into \(\mathrm{5m + b = 44}\):
- \(\mathrm{5(2b) + b = 44}\)
- \(\mathrm{10b + b = 44}\)
- \(\mathrm{11b = 44}\)
- \(\mathrm{b = 4}\)
5. Find the hourly rate
- Since \(\mathrm{m = 2b}\) and \(\mathrm{b = 4}\):
- \(\mathrm{m = 2(4) = 8}\)
6. Calculate the 10-hour job cost
- \(\mathrm{C(10) = m(10) + b}\)
- \(\mathrm{C(10) = 8(10) + 4}\)
- \(\mathrm{C(10) = 80 + 4}\)
- \(\mathrm{C(10) = 84}\)
Answer: 84
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak TRANSLATE skill: Students often struggle to correctly identify what "twice the flat fee" means mathematically, writing \(\mathrm{b = 2m}\) instead of \(\mathrm{m = 2b}\).
When they use \(\mathrm{b = 2m}\), they get:
\(\mathrm{5m + b = 44}\)
\(\mathrm{5m + 2m = 44}\)
\(\mathrm{7m = 44}\)
\(\mathrm{m = \frac{44}{7} \approx 6.29}\)
Then \(\mathrm{b = 2(\frac{44}{7}) = \frac{88}{7} \approx 12.57}\)
For 10 hours:
\(\mathrm{C(10) = (\frac{44}{7})(10) + \frac{88}{7}}\)
\(\mathrm{C(10) = \frac{440}{7} + \frac{88}{7}}\)
\(\mathrm{C(10) = \frac{528}{7} \approx 75.4}\)
This leads to confusion since 75.4 isn't a clean integer answer, causing them to guess or round incorrectly.
Second Most Common Error:
Poor INFER reasoning: Students set up the equations correctly but don't recognize they need to use substitution to solve the system. Instead, they try to solve \(\mathrm{5m + b = 44}\) and \(\mathrm{m = 2b}\) separately or get confused about which equation to use first.
This causes them to get stuck early in the problem and resort to guessing.
The Bottom Line:
This problem tests whether students can correctly translate verbal constraints into mathematical relationships and then systematically use substitution to solve a constrained system. The key insight is recognizing that "hourly rate is twice the flat fee" means \(\mathrm{m = 2b}\), not the reverse.