The function h is defined by \(\mathrm{h(x) = 4x + 28}\). The graph of \(\mathrm{y = h(x)}\) in the xy-plane...
GMAT Algebra : (Alg) Questions
The function h is defined by \(\mathrm{h(x) = 4x + 28}\). The graph of \(\mathrm{y = h(x)}\) in the xy-plane has an x-intercept at \(\mathrm{(a, 0)}\) and a y-intercept at \(\mathrm{(0, b)}\), where a and b are constants. What is the value of \(\mathrm{a + b}\)?
21
28
32
35
1. TRANSLATE the problem information
- Given information:
- Function: \(\mathrm{h(x) = 4x + 28}\)
- Graph has x-intercept at \(\mathrm{(a, 0)}\) and y-intercept at \(\mathrm{(0, b)}\)
- Need to find: \(\mathrm{a + b}\)
- What this tells us: We need to find where the graph crosses both axes
2. INFER the approach
- To find intercepts, we substitute specific values:
- X-intercept: set \(\mathrm{y = 0}\) and solve for x
- Y-intercept: set \(\mathrm{x = 0}\) and solve for y
- The function \(\mathrm{y = h(x)}\) becomes \(\mathrm{y = 4x + 28}\)
3. SIMPLIFY to find the x-intercept
- Set \(\mathrm{y = 0}\): \(\mathrm{0 = 4x + 28}\)
- Subtract 28: \(\mathrm{-28 = 4x}\)
- Divide by 4: \(\mathrm{x = -7}\)
- So \(\mathrm{a = -7}\) (the x-coordinate of the x-intercept)
4. SIMPLIFY to find the y-intercept
- Set \(\mathrm{x = 0}\): \(\mathrm{y = 4(0) + 28}\)
- Calculate: \(\mathrm{y = 28}\)
- So \(\mathrm{b = 28}\) (the y-coordinate of the y-intercept)
5. Calculate final answer
- \(\mathrm{a + b = -7 + 28 = 21}\)
Answer: A. 21
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak SIMPLIFY skill: Students make a sign error when solving \(\mathrm{-28 = 4x}\), dividing incorrectly to get \(\mathrm{x = 7}\) instead of \(\mathrm{x = -7}\).
When they calculate \(\mathrm{7 + 28 = 35}\), this leads them to select Choice D (35).
Second Most Common Error:
Poor TRANSLATE reasoning: Students confuse the coordinates, thinking the x-intercept gives them the y-value they need, or mixing up which variable to set to zero.
This leads to confusion about what a and b represent, causing them to get stuck and guess among the remaining choices.
The Bottom Line:
This problem tests whether students can correctly connect the geometric concept of intercepts with the algebraic process of substitution, while maintaining accuracy through negative number arithmetic.
21
28
32
35