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The function h is defined by \(\mathrm{h(x) = 4x + 28}\). The graph of \(\mathrm{y = h(x)}\) in the xy-plane...

GMAT Algebra : (Alg) Questions

Source: Practice Test
Algebra
Linear functions
MEDIUM
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Notes
Post a Query

The function h is defined by \(\mathrm{h(x) = 4x + 28}\). The graph of \(\mathrm{y = h(x)}\) in the xy-plane has an x-intercept at \(\mathrm{(a, 0)}\) and a y-intercept at \(\mathrm{(0, b)}\), where a and b are constants. What is the value of \(\mathrm{a + b}\)?

A

21

B

28

C

32

D

35

Solution

1. TRANSLATE the problem information

  • Given information:
    • Function: \(\mathrm{h(x) = 4x + 28}\)
    • Graph has x-intercept at \(\mathrm{(a, 0)}\) and y-intercept at \(\mathrm{(0, b)}\)
    • Need to find: \(\mathrm{a + b}\)
  • What this tells us: We need to find where the graph crosses both axes

2. INFER the approach

  • To find intercepts, we substitute specific values:
    • X-intercept: set \(\mathrm{y = 0}\) and solve for x
    • Y-intercept: set \(\mathrm{x = 0}\) and solve for y
  • The function \(\mathrm{y = h(x)}\) becomes \(\mathrm{y = 4x + 28}\)

3. SIMPLIFY to find the x-intercept

  • Set \(\mathrm{y = 0}\): \(\mathrm{0 = 4x + 28}\)
  • Subtract 28: \(\mathrm{-28 = 4x}\)
  • Divide by 4: \(\mathrm{x = -7}\)
  • So \(\mathrm{a = -7}\) (the x-coordinate of the x-intercept)

4. SIMPLIFY to find the y-intercept

  • Set \(\mathrm{x = 0}\): \(\mathrm{y = 4(0) + 28}\)
  • Calculate: \(\mathrm{y = 28}\)
  • So \(\mathrm{b = 28}\) (the y-coordinate of the y-intercept)

5. Calculate final answer

  • \(\mathrm{a + b = -7 + 28 = 21}\)

Answer: A. 21


Why Students Usually Falter on This Problem

Most Common Error Path:

Weak SIMPLIFY skill: Students make a sign error when solving \(\mathrm{-28 = 4x}\), dividing incorrectly to get \(\mathrm{x = 7}\) instead of \(\mathrm{x = -7}\).

When they calculate \(\mathrm{7 + 28 = 35}\), this leads them to select Choice D (35).

Second Most Common Error:

Poor TRANSLATE reasoning: Students confuse the coordinates, thinking the x-intercept gives them the y-value they need, or mixing up which variable to set to zero.

This leads to confusion about what a and b represent, causing them to get stuck and guess among the remaining choices.

The Bottom Line:

This problem tests whether students can correctly connect the geometric concept of intercepts with the algebraic process of substitution, while maintaining accuracy through negative number arithmetic.

Answer Choices Explained
A

21

B

28

C

32

D

35

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