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Question:\(\mathrm{h(x) = 6(3)^x}\)The function h is defined by the given equation. If \(\mathrm{j(x) = h(x - 1)}\), which of the...

GMAT Advanced Math : (Adv_Math) Questions

Source: Prism
Advanced Math
Nonlinear functions
HARD
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Question:

\(\mathrm{h(x) = 6(3)^x}\)

The function h is defined by the given equation. If \(\mathrm{j(x) = h(x - 1)}\), which of the following equations defines the function j?

A

\(\mathrm{j(x) = 2(3)^x}\)

B

\(\mathrm{j(x) = 18(3)^x}\)

C

\(\mathrm{j(x) = 6(2)^x}\)

D

\(\mathrm{j(x) = 6(3)^{(x-1)}}\)

Solution

1. TRANSLATE the function relationship

  • Given information:
    • \(\mathrm{h(x) = 6(3)^x}\)
    • \(\mathrm{j(x) = h(x - 1)}\)
  • What this means: Wherever we see x in h(x), we replace it with (x - 1)

2. TRANSLATE into mathematical form

  • Substitute (x - 1) into h(x):
    \(\mathrm{j(x) = h(x - 1) = 6(3)^{(x-1)}}\)
  • This gives us \(\mathrm{j(x) = 6(3)^{(x-1)}}\)

3. SIMPLIFY using exponent rules

  • Apply the rule \(\mathrm{a^{(m-n)} = a^m \times a^{(-n)}}\):
    \(\mathrm{6(3)^{(x-1)} = 6 \times 3^x \times 3^{(-1)}}\)
  • Since \(\mathrm{3^{(-1)} = \frac{1}{3}}\):
    \(\mathrm{= 6 \times 3^x \times \left(\frac{1}{3}\right)}\)
  • Multiply the constants:
    \(\mathrm{= \left(\frac{6}{3}\right) \times 3^x = 2 \times 3^x = 2(3)^x}\)

Answer: A




Why Students Usually Falter on This Problem


Most Common Error Path:

Weak SIMPLIFY execution: Students correctly get to \(\mathrm{j(x) = 6(3)^{(x-1)}}\) but then struggle with the exponent rules. They might try to "distribute" the exponent: \(\mathrm{6(3)^{(x-1)} = 6(3^x - 3^1) = 6(3^x - 3) = 6(3^x) - 18}\), leading to confusion since this doesn't match any answer choice format. This leads to guessing among the choices.


Second Most Common Error:

Incomplete TRANSLATE reasoning: Some students see \(\mathrm{j(x) = h(x-1)}\) and think it means "shift the coefficient" rather than "substitute (x-1) for x." They might incorrectly reason that since \(\mathrm{h(x) = 6(3)^x}\), then j(x) should be \(\mathrm{6(3)^x}\) multiplied by 3 (thinking about horizontal shifts incorrectly), leading them toward Choice B (\(\mathrm{18(3)^x}\)).


The Bottom Line:

This problem tests whether students can properly execute function substitution followed by careful algebraic simplification. The key insight is that \(\mathrm{j(x) = h(x-1)}\) means literal substitution, not a transformation of the function's graph properties.

Answer Choices Explained
A

\(\mathrm{j(x) = 2(3)^x}\)

B

\(\mathrm{j(x) = 18(3)^x}\)

C

\(\mathrm{j(x) = 6(2)^x}\)

D

\(\mathrm{j(x) = 6(3)^{(x-1)}}\)

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