The table shows selected values of a function h, where \(\mathrm{h(x) = \frac{x - 2}{f(x)}}\) and f is a linear...
GMAT Advanced Math : (Adv_Math) Questions
The table shows selected values of a function h, where \(\mathrm{h(x) = \frac{x - 2}{f(x)}}\) and f is a linear function. What is the y-intercept of the graph of \(\mathrm{y = f(x)}\) in the xy-plane?
| x | \(\mathrm{h(x)}\) |
|---|---|
| -5 | \(\mathrm{\frac{7}{9}}\) |
| 1 | \(\mathrm{\frac{-1}{9}}\) |
| 4 | \(\mathrm{\frac{1}{9}}\) |
- \(\mathrm{(0, -6)}\)
- \(\mathrm{(0, 4)}\)
- \(\mathrm{(0, 6)}\)
- \(\mathrm{(0, 9)}\)
1. TRANSLATE the problem information
- Given information:
- \(\mathrm{h(x) = \frac{x - 2}{f(x)}}\) where f is linear
- Table with three \(\mathrm{(x, h(x))}\) pairs
- We need: y-intercept of \(\mathrm{f(x)}\)
2. INFER the approach
- Since we have \(\mathrm{h(x)}\) but need information about \(\mathrm{f(x)}\), we should rearrange the given relationship
- From \(\mathrm{h(x) = \frac{x - 2}{f(x)}}\), we can solve for \(\mathrm{f(x)}\): \(\mathrm{f(x) = \frac{x - 2}{h(x)}}\)
- This will give us actual points on the linear function \(\mathrm{f(x)}\)
3. SIMPLIFY to find f(x) values
- At \(\mathrm{x = -5}\): \(\mathrm{f(-5) = \frac{-5 - 2}{7/9}}\)
\(\mathrm{= -7 \div \frac{7}{9}}\)
\(\mathrm{= -7 \times \frac{9}{7}}\)
\(\mathrm{= -9}\) - At \(\mathrm{x = 1}\): \(\mathrm{f(1) = \frac{1 - 2}{-1/9}}\)
\(\mathrm{= -1 \div \frac{-1}{9}}\)
\(\mathrm{= -1 \times (-9)}\)
\(\mathrm{= 9}\) - At \(\mathrm{x = 4}\): \(\mathrm{f(4) = \frac{4 - 2}{1/9}}\)
\(\mathrm{= 2 \div \frac{1}{9}}\)
\(\mathrm{= 2 \times 9}\)
\(\mathrm{= 18}\)
4. INFER how to use the linear nature
- Since f is linear, it has the form \(\mathrm{f(x) = mx + b}\)
- We can use any two points to find the slope m, then find b
5. SIMPLIFY to find slope and y-intercept
- Using points \(\mathrm{(1, 9)}\) and \(\mathrm{(4, 18)}\):
- Slope: \(\mathrm{m = \frac{18 - 9}{4 - 1}}\)
\(\mathrm{= \frac{9}{3}}\)
\(\mathrm{= 3}\) - Using point \(\mathrm{(1, 9)}\): \(\mathrm{9 = 3(1) + b}\)
\(\mathrm{b = 6}\)
Answer: C. (0, 6)
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak INFER skill: Students see \(\mathrm{h(x) = \frac{x - 2}{f(x)}}\) but don't recognize they need to rearrange this to find \(\mathrm{f(x)}\) values. Instead, they might try to work directly with the \(\mathrm{h(x)}\) values or attempt to substitute into a general linear form without first finding actual points on \(\mathrm{f(x)}\). This leads to confusion and guessing.
Second Most Common Error:
Poor SIMPLIFY execution: Students correctly identify that \(\mathrm{f(x) = \frac{x - 2}{h(x)}}\) but make errors when dividing by fractions. For example, calculating \(\mathrm{f(-5) = \frac{-7}{7/9}}\) incorrectly as \(\mathrm{(-7) \times \frac{7}{9}}\) instead of \(\mathrm{(-7) \times \frac{9}{7}}\). This gives wrong \(\mathrm{f(x)}\) values, leading to incorrect slope and y-intercept calculations. This may lead them to select Choice A (0, -6) or Choice D (0, 9).
The Bottom Line:
This problem requires students to think backwards from the composed function \(\mathrm{h(x)}\) to recover the original linear function \(\mathrm{f(x)}\), then apply standard linear function techniques. The key insight is recognizing the algebraic rearrangement needed to extract useful information.