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The formula E = 1/2mv^2 gives the kinetic energy E of an object with mass m moving at speed v....

GMAT Advanced Math : (Adv_Math) Questions

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Advanced Math
Nonlinear equations in 1 variable
MEDIUM
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Notes
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The formula \(\mathrm{E = \frac{1}{2}mv^2}\) gives the kinetic energy \(\mathrm{E}\) of an object with mass \(\mathrm{m}\) moving at speed \(\mathrm{v}\). Which of the following correctly expresses the speed \(\mathrm{v}\) in terms of \(\mathrm{E}\) and \(\mathrm{m}\)?

A
\(\mathrm{v = \sqrt{\frac{2E}{m}}}\)
B
\(\mathrm{v = \sqrt{\frac{E}{2m}}}\)
C
\(\mathrm{v = \frac{2E}{m}}\)
D
\(\mathrm{v = \frac{E}{2m}}\)
Solution

1. INFER the solution strategy

  • Goal: Isolate the variable v on one side of the equation
  • Strategy: Undo operations affecting v in reverse order
  • Current situation: v is squared, multiplied by m, multiplied by ½

2. SIMPLIFY by eliminating the fraction first

  • Start with: \(\mathrm{E = \frac{1}{2}mv^2}\)
  • Multiply both sides by 2: \(\mathrm{2E = mv^2}\)
  • This removes the fraction and makes subsequent steps cleaner

3. SIMPLIFY by isolating v²

  • From: \(\mathrm{2E = mv^2}\)
  • Divide both sides by m: \(\mathrm{\frac{2E}{m} = v^2}\)
  • Now v² is isolated on the right side

4. SIMPLIFY by taking the square root

  • From: \(\mathrm{\frac{2E}{m} = v^2}\)
  • Take square root of both sides: \(\mathrm{v = \sqrt{\frac{2E}{m}}}\)
  • This gives us v isolated completely

Answer: A. v = \(\mathrm{\sqrt{\frac{2E}{m}}}\)




Why Students Usually Falter on This Problem

Most Common Error Path:

Weak SIMPLIFY execution: Students correctly multiply by 2 but then make an error in the fraction manipulation, thinking they should divide E by 2m instead of multiplying E by 2 first.

Their work might look like:

\(\mathrm{E = \frac{1}{2}mv^2}\)

\(\mathrm{v^2 = \frac{E}{\frac{1}{2}m}}\)

\(\mathrm{v^2 = \frac{E}{2m}}\)

\(\mathrm{v = \sqrt{\frac{E}{2m}}}\)

This may lead them to select Choice B (\(\mathrm{\sqrt{\frac{E}{2m}}}\))

Second Most Common Error:

Poor INFER reasoning: Students correctly eliminate the fraction and isolate v², but forget that they need to take the square root to solve for v (not v²).

Their work stops at: \(\mathrm{\frac{2E}{m} = v^2}\), and they think this means \(\mathrm{v = \frac{2E}{m}}\)

This may lead them to select Choice C (\(\mathrm{\frac{2E}{m}}\))

The Bottom Line:

This problem tests systematic algebraic manipulation skills. Success requires carefully undoing each operation that affects the target variable v, in the proper reverse order, while maintaining algebraic accuracy throughout.

Answer Choices Explained
A
\(\mathrm{v = \sqrt{\frac{2E}{m}}}\)
B
\(\mathrm{v = \sqrt{\frac{E}{2m}}}\)
C
\(\mathrm{v = \frac{2E}{m}}\)
D
\(\mathrm{v = \frac{E}{2m}}\)
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