The formula E = 1/2mv^2 gives the kinetic energy E of an object with mass m moving at speed v....
GMAT Advanced Math : (Adv_Math) Questions
The formula \(\mathrm{E = \frac{1}{2}mv^2}\) gives the kinetic energy \(\mathrm{E}\) of an object with mass \(\mathrm{m}\) moving at speed \(\mathrm{v}\). Which of the following correctly expresses the speed \(\mathrm{v}\) in terms of \(\mathrm{E}\) and \(\mathrm{m}\)?
1. INFER the solution strategy
- Goal: Isolate the variable v on one side of the equation
- Strategy: Undo operations affecting v in reverse order
- Current situation: v is squared, multiplied by m, multiplied by ½
2. SIMPLIFY by eliminating the fraction first
- Start with: \(\mathrm{E = \frac{1}{2}mv^2}\)
- Multiply both sides by 2: \(\mathrm{2E = mv^2}\)
- This removes the fraction and makes subsequent steps cleaner
3. SIMPLIFY by isolating v²
- From: \(\mathrm{2E = mv^2}\)
- Divide both sides by m: \(\mathrm{\frac{2E}{m} = v^2}\)
- Now v² is isolated on the right side
4. SIMPLIFY by taking the square root
- From: \(\mathrm{\frac{2E}{m} = v^2}\)
- Take square root of both sides: \(\mathrm{v = \sqrt{\frac{2E}{m}}}\)
- This gives us v isolated completely
Answer: A. v = \(\mathrm{\sqrt{\frac{2E}{m}}}\)
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak SIMPLIFY execution: Students correctly multiply by 2 but then make an error in the fraction manipulation, thinking they should divide E by 2m instead of multiplying E by 2 first.
Their work might look like:
\(\mathrm{E = \frac{1}{2}mv^2}\)
\(\mathrm{v^2 = \frac{E}{\frac{1}{2}m}}\)
\(\mathrm{v^2 = \frac{E}{2m}}\)
\(\mathrm{v = \sqrt{\frac{E}{2m}}}\)
This may lead them to select Choice B (\(\mathrm{\sqrt{\frac{E}{2m}}}\))
Second Most Common Error:
Poor INFER reasoning: Students correctly eliminate the fraction and isolate v², but forget that they need to take the square root to solve for v (not v²).
Their work stops at: \(\mathrm{\frac{2E}{m} = v^2}\), and they think this means \(\mathrm{v = \frac{2E}{m}}\)
This may lead them to select Choice C (\(\mathrm{\frac{2E}{m}}\))
The Bottom Line:
This problem tests systematic algebraic manipulation skills. Success requires carefully undoing each operation that affects the target variable v, in the proper reverse order, while maintaining algebraic accuracy throughout.