The function \(\mathrm{k(x) = ax + 7}\), where a is a constant. If \(\mathrm{k(3) - k(1) = 10}\), what is...
GMAT Algebra : (Alg) Questions
The function \(\mathrm{k(x) = ax + 7}\), where \(\mathrm{a}\) is a constant. If \(\mathrm{k(3) - k(1) = 10}\), what is the value of \(\mathrm{a}\)?
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1. TRANSLATE the problem information
- Given information:
- \(\mathrm{k(x) = ax + 7}\) (linear function with unknown coefficient a)
- \(\mathrm{k(3) - k(1) = 10}\) (condition relating two function values)
- What this tells us: We need to find the specific value of coefficient a
2. TRANSLATE the function values
- Evaluate each function value by substituting:
- \(\mathrm{k(3) = a(3) + 7 = 3a + 7}\)
- \(\mathrm{k(1) = a(1) + 7 = a + 7}\)
3. TRANSLATE the given condition into an equation
- Set up the equation: \(\mathrm{k(3) - k(1) = 10}\)
- Substitute our expressions: \(\mathrm{(3a + 7) - (a + 7) = 10}\)
4. SIMPLIFY the equation algebraically
- Distribute the negative sign carefully: \(\mathrm{3a + 7 - a - 7 = 10}\)
- Combine like terms: \(\mathrm{2a = 10}\)
- Solve for a: \(\mathrm{a = 5}\)
Answer: C (5)
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak SIMPLIFY execution: Making sign errors when subtracting \(\mathrm{(a + 7)}\)
Students often write: \(\mathrm{(3a + 7) - (a + 7) = 3a + 7 - a + 7 = 2a + 14}\)
This gives them \(\mathrm{2a + 14 = 10}\), so \(\mathrm{2a = -4}\), and \(\mathrm{a = -2}\). Since this isn't among the choices, they may get confused and select Choice A (2) by dropping the negative sign or making another computational error.
Second Most Common Error:
Poor TRANSLATE reasoning: Misunderstanding what \(\mathrm{k(3) - k(1) = 10}\) means
Some students might think this means k(3) should equal 10 by itself, leading them to solve \(\mathrm{3a + 7 = 10}\), which gives \(\mathrm{3a = 3}\), so \(\mathrm{a = 1}\). Since 1 isn't a choice, they might guess or select Choice B (3) as the coefficient they calculated.
The Bottom Line:
This problem tests your ability to work systematically with function notation and maintain accuracy through algebraic manipulation. The key is careful attention to signs when subtracting expressions.
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