A software company charges $180 for a license that covers up to 3 users. For each additional user beyond the...
GMAT Algebra : (Alg) Questions
A software company charges $180 for a license that covers up to 3 users. For each additional user beyond the first 3, the company charges an extra $45. Which of the following functions gives the total cost \(\mathrm{C(n)}\), in dollars, for a license covering \(\mathrm{n}\) users, where \(\mathrm{n}\) is a positive integer and \(\mathrm{n ≥ 3}\)?
\(\mathrm{C(n) = 45n + 45}\)
\(\mathrm{C(n) = 45n + 180}\)
\(\mathrm{C(n) = 45n + 135}\)
\(\mathrm{C(n) = 180n - 135}\)
1. TRANSLATE the problem information
- Given information:
- Base license cost: $180 for up to 3 users
- Additional user cost: $45 for each user beyond the first 3
- Need function C(n) for n users where \(\mathrm{n \geq 3}\)
2. INFER the cost structure
- This is a two-part pricing model: base cost + additional charges
- Key insight: For n users total, the number of "additional users beyond the first 3" is \(\mathrm{(n - 3)}\)
- Total cost = Base cost + (Additional users) × (Cost per additional user)
3. TRANSLATE into mathematical expression
- \(\mathrm{C(n) = 180 + (n - 3) \times 45}\)
- \(\mathrm{C(n) = 180 + 45(n - 3)}\)
4. SIMPLIFY the expression
- \(\mathrm{C(n) = 180 + 45(n - 3)}\)
- \(\mathrm{C(n) = 180 + 45n - 135}\)
- \(\mathrm{C(n) = 45n + 45}\)
5. Verify with test cases
- For \(\mathrm{n = 3}\): \(\mathrm{C(3) = 45(3) + 45 = 180}\) ✓
- For \(\mathrm{n = 4}\): \(\mathrm{C(4) = 45(4) + 45 = 225}\) (should be $180 + $45 = $225) ✓
Answer: (A) \(\mathrm{C(n) = 45n + 45}\)
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak INFER skill: Students misunderstand what "additional users beyond the first 3" means and think there are n additional users instead of \(\mathrm{(n - 3)}\) additional users.
They set up the function as \(\mathrm{C(n) = 180 + 45n}\), reasoning that you pay $180 base plus $45 for each of the n users. This leads them to select Choice (B) (\(\mathrm{C(n) = 45n + 180}\)).
Second Most Common Error:
Poor SIMPLIFY execution: Students correctly set up \(\mathrm{180 + 45(n - 3)}\) but make algebraic errors when expanding or combining like terms.
Common mistakes include getting \(\mathrm{180 + 45n - 45 = 45n + 135}\), which leads them to select Choice (C) (\(\mathrm{C(n) = 45n + 135}\)).
The Bottom Line:
This problem tests whether students can correctly interpret "additional beyond the first few" language and translate it into the mathematical expression \(\mathrm{(n - 3)}\). The key insight is understanding that if you have n users total and the first 3 are covered by the base price, then only \(\mathrm{(n - 3)}\) users incur the additional charge.
\(\mathrm{C(n) = 45n + 45}\)
\(\mathrm{C(n) = 45n + 180}\)
\(\mathrm{C(n) = 45n + 135}\)
\(\mathrm{C(n) = 180n - 135}\)