In the xy-plane, line k is defined by x + y = 0. Line j is perpendicular to line k,...
GMAT Algebra : (Alg) Questions
In the xy-plane, line k is defined by \(\mathrm{x + y = 0}\). Line j is perpendicular to line k, and the y-intercept of line j is \(\mathrm{(0, 3)}\). Which of the following is an equation of line j?
\(\mathrm{x + y = 3}\)
\(\mathrm{x + y = -3}\)
\(\mathrm{x - y = 3}\)
\(\mathrm{x - y = -3}\)
1. TRANSLATE the problem information
- Given information:
- Line k: \(\mathrm{x + y = 0}\)
- Line j is perpendicular to line k
- Line j has y-intercept (0, 3)
- Need equation of line j
2. INFER the approach
- To find line j's equation, I need its slope and y-intercept
- I already have the y-intercept (0, 3)
- To find the slope, I need to use the perpendicular relationship with line k
- This means I first need to find line k's slope
3. SIMPLIFY line k to find its slope
- Rewrite \(\mathrm{x + y = 0}\) in slope-intercept form:
\(\mathrm{x + y = 0}\)
\(\mathrm{y = -x}\)
- The slope of line k is \(\mathrm{-1}\)
4. INFER the slope of line j
- Since line j is perpendicular to line k, their slopes are negative reciprocals
- If line k has slope \(\mathrm{-1}\), then line j has slope: \(\mathrm{-1/(-1) = 1}\)
5. INFER the equation of line j
- Line j has slope 1 and y-intercept (0, 3)
- Using slope-intercept form: \(\mathrm{y = 1x + 3}\), or \(\mathrm{y = x + 3}\)
6. SIMPLIFY to match answer format
- Convert \(\mathrm{y = x + 3}\) to standard form:
\(\mathrm{y = x + 3}\)
\(\mathrm{x - y = -3}\)
Answer: D. \(\mathrm{x - y = -3}\)
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak INFER skill: Students don't recognize that perpendicular lines have slopes that are negative reciprocals—they think perpendicular lines have the same slope (like parallel lines do).
With slope \(\mathrm{-1}\) for both lines and y-intercept (0, 3), they get \(\mathrm{y = -x + 3}\), which converts to \(\mathrm{x + y = -3}\).
This may lead them to select Choice B (\(\mathrm{x + y = -3}\))
Second Most Common Error:
Poor SIMPLIFY execution: Students correctly find that line j should have slope 1 and get \(\mathrm{y = x + 3}\), but make sign errors when converting to standard form.
They might rearrange as \(\mathrm{x - y = 3}\) instead of \(\mathrm{x - y = -3}\).
This may lead them to select Choice C (\(\mathrm{x - y = 3}\))
The Bottom Line:
This problem tests whether students truly understand the perpendicular line relationship (negative reciprocals, not same slopes) and can accurately convert between equation forms without sign errors.
\(\mathrm{x + y = 3}\)
\(\mathrm{x + y = -3}\)
\(\mathrm{x - y = 3}\)
\(\mathrm{x - y = -3}\)