Line k in the xy-plane has a slope of -{2} and passes through the point \(\mathrm{(3, 1)}\). Which of the...
GMAT Algebra : (Alg) Questions
Line \(\mathrm{k}\) in the \(\mathrm{xy}\)-plane has a slope of \(\mathrm{-2}\) and passes through the point \(\mathrm{(3, 1)}\). Which of the following is an equation of line \(\mathrm{k}\)?
1. TRANSLATE the problem information
- Given information:
- Slope of line k: \(\mathrm{m = -2}\)
- Line k passes through point \(\mathrm{(3, 1)}\)
- Find: equation of line k
2. INFER the approach needed
- Since we have the slope, use slope-intercept form: \(\mathrm{y = mx + b}\)
- We know \(\mathrm{m = -2}\), so our equation is \(\mathrm{y = -2x + b}\)
- We need to find the y-intercept b using the given point
3. INFER the substitution strategy
- Since point \(\mathrm{(3, 1)}\) lies on the line, it must satisfy the equation
- Substitute \(\mathrm{x = 3}\) and \(\mathrm{y = 1}\) into \(\mathrm{y = -2x + b}\)
4. SIMPLIFY to find the y-intercept
- Start with: \(\mathrm{1 = -2(3) + b}\)
- Calculate: \(\mathrm{1 = -6 + b}\)
- Add 6 to both sides: \(\mathrm{1 + 6 = b}\)
- Therefore: \(\mathrm{b = 7}\)
5. Write the final equation
- \(\mathrm{y = -2x + 7}\)
Answer: C (\(\mathrm{y = -2x + 7}\))
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak TRANSLATE skill: Students confuse the given point \(\mathrm{(3, 1)}\) with the y-intercept, thinking that since \(\mathrm{y = 1}\) when we have some point, the y-intercept must be 1.
They incorrectly assume \(\mathrm{b = 1}\) and write \(\mathrm{y = -2x + 1}\).
This leads them to select Choice B (\(\mathrm{y = -2x + 1}\)).
Second Most Common Error:
Poor SIMPLIFY execution: Students make arithmetic errors when solving \(\mathrm{1 = -6 + b}\), such as getting \(\mathrm{b = -5}\) instead of \(\mathrm{b = 7}\).
For example:
\(\mathrm{1 = -6 + b}\)
\(\mathrm{1 - 6 = b}\) (wrong sign)
\(\mathrm{b = -5}\)
This may lead them to select Choice A (\(\mathrm{y = -2x - 5}\)).
The Bottom Line:
This problem tests whether students understand that any point on a line must satisfy the line's equation - not just special points like intercepts. The key insight is using the given point to find the unknown y-intercept.