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A line passes through the point \((1, 8)\) and has a slope of -{2}. What is the x-intercept of the...

GMAT Algebra : (Alg) Questions

Source: Prism
Algebra
Linear functions
MEDIUM
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Notes
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A line passes through the point \((1, 8)\) and has a slope of \(-2\). What is the \(\mathrm{x}\)-intercept of the graph of the line in the \(\mathrm{xy}\)-plane?

A

\((-5, 0)\)

B

\((1, 0)\)

C

\((5, 0)\)

D

\((10, 0)\)

Solution

1. TRANSLATE the problem information

  • Given information:
    • Point on line: \((1, 8)\)
    • Slope: \(\mathrm{m = -2}\)
    • Need to find: x-intercept (where line crosses x-axis)
  • What this tells us: We need to find where \(\mathrm{y = 0}\)

2. INFER the approach

  • To find the x-intercept, we need the line's equation first
  • Then set \(\mathrm{y = 0}\) and solve for x
  • Point-slope form works perfectly since we have a point and the slope

3. TRANSLATE into point-slope form

  • Using \(\mathrm{y - y_1 = m(x - x_1)}\):
  • \(\mathrm{y - 8 = -2(x - 1)}\)

4. INFER the next step to find x-intercept

  • Set \(\mathrm{y = 0}\) (definition of x-intercept):
  • \(\mathrm{0 - 8 = -2(x - 1)}\)

5. SIMPLIFY through algebraic steps

  • \(\mathrm{-8 = -2(x - 1)}\)
  • \(\mathrm{-8 = -2x + 2}\)
  • \(\mathrm{-8 - 2 = -2x}\)
  • \(\mathrm{-10 = -2x}\)
  • \(\mathrm{x = 5}\)

6. TRANSLATE back to coordinate form

  • The x-intercept is \((5, 0)\)

Answer: C \((5, 0)\)




Why Students Usually Falter on This Problem

Most Common Error Path:

Weak TRANSLATE skill: Students confuse what "x-intercept" means and try to substitute \(\mathrm{x = 0}\) instead of \(\mathrm{y = 0}\).

This leads them to find: \(\mathrm{0 - 8 = -2(0 - 1)}\), which gives \(\mathrm{-8 = 2}\), resulting in confusion. They might then guess or incorrectly think the y-intercept \((0, 10)\) relates to the x-intercept somehow, possibly leading them to select Choice D \((10, 0)\).

Second Most Common Error:

Poor SIMPLIFY execution: Students correctly set up \(\mathrm{0 - 8 = -2(x - 1)}\) but make algebraic errors.

Common mistake: \(\mathrm{-8 = -2(x - 1)}\) becomes \(\mathrm{-8 = -2x - 2}\) (wrong sign on the 2), leading to \(\mathrm{-8 + 2 = -2x}\), so \(\mathrm{-6 = -2x}\), giving \(\mathrm{x = 3}\). Since \((3, 0)\) isn't an option, this causes confusion and guessing.

The Bottom Line:

This problem tests whether students truly understand what an x-intercept represents and can systematically work through the algebra without sign errors.

Answer Choices Explained
A

\((-5, 0)\)

B

\((1, 0)\)

C

\((5, 0)\)

D

\((10, 0)\)

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