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Line s is perpendicular to the line defined by y = 3x - 2 and passes through the point \(\mathrm{(9,...

GMAT Algebra : (Alg) Questions

Source: Prism
Algebra
Linear equations in 2 variables
MEDIUM
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Notes
Post a Query

Line s is perpendicular to the line defined by \(\mathrm{y = 3x - 2}\) and passes through the point \(\mathrm{(9, 5)}\). Which equation defines line s?

  1. \(\mathrm{y = -\frac{x}{3} + 8}\)
  2. \(\mathrm{y = 3x - 22}\)
  3. \(\mathrm{y = -3x + 32}\)
  4. \(\mathrm{y = -\frac{x}{3} + 6}\)
A
\(\mathrm{y = -\frac{x}{3} + 8}\)
B
\(\mathrm{y = 3x - 22}\)
C
\(\mathrm{y = -3x + 32}\)
D
\(\mathrm{y = -\frac{x}{3} + 6}\)
Solution

1. TRANSLATE the problem information

  • Given information:
    • Line s is perpendicular to \(\mathrm{y = 3x - 2}\)
    • Line s passes through point \(\mathrm{(9, 5)}\)
    • Need to find equation of line s

2. INFER the perpendicular slope relationship

  • The given line \(\mathrm{y = 3x - 2}\) has \(\mathrm{slope = 3}\)
  • Key insight: Perpendicular lines have slopes that are negative reciprocals
  • Therefore, \(\mathrm{slope\ of\ line\ s = -\frac{1}{3}}\)

3. SIMPLIFY using point-slope form

  • Use \(\mathrm{y = mx + b}\) with point \(\mathrm{(9, 5)}\) and slope \(\mathrm{-\frac{1}{3}}\):
  • Substitute: \(\mathrm{5 = (-\frac{1}{3})(9) + b}\)
  • Calculate: \(\mathrm{5 = -3 + b}\)
  • Solve: \(\mathrm{b = 8}\)

4. Write the final equation

  • Line s: \(\mathrm{y = -\frac{x}{3} + 8}\)

Answer: A




Why Students Usually Falter on This Problem


Most Common Error Path:

Weak INFER skill: Not recognizing the negative reciprocal relationship for perpendicular slopes

Students might think perpendicular lines have the same slope or opposite slopes (like 3 and -3), rather than negative reciprocals. They might incorrectly use \(\mathrm{slope = -3}\) instead of \(\mathrm{slope = -\frac{1}{3}}\).

This may lead them to select Choice C (\(\mathrm{y = -3x + 32}\)).


Second Most Common Error:

Poor SIMPLIFY execution: Arithmetic errors when solving for the y-intercept

Students correctly identify \(\mathrm{slope = -\frac{1}{3}}\) but make calculation mistakes:

  • Wrong: \(\mathrm{5 = -3 + b}\)\(\mathrm{b = 2}\) (instead of \(\mathrm{b = 8}\))
  • Or sign errors in the arithmetic

This may lead them to select Choice D (\(\mathrm{y = -\frac{x}{3} + 6}\)) or cause confusion and guessing.


The Bottom Line:

The key challenge is remembering that perpendicular slopes are negative reciprocals, not just negatives. Students who memorize this relationship and execute careful arithmetic will solve this successfully.

Answer Choices Explained
A
\(\mathrm{y = -\frac{x}{3} + 8}\)
B
\(\mathrm{y = 3x - 22}\)
C
\(\mathrm{y = -3x + 32}\)
D
\(\mathrm{y = -\frac{x}{3} + 6}\)
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