Line s in the xy-plane has a slope of -{2} and passes through the point \((3,1)\). Which equation defines line...
GMAT Algebra : (Alg) Questions
- \(\mathrm{y = -2x - 5}\)
- \(\mathrm{y = -2x + 1}\)
- \(\mathrm{y = -2x + 7}\)
- \(\mathrm{y = 2x + 7}\)
1. TRANSLATE the problem information
- Given information:
- Slope \(\mathrm{(m) = -2}\)
- Point on line: \(\mathrm{(3, 1)}\)
- Need to find: The equation of line s in slope-intercept form \(\mathrm{(y = mx + b)}\)
2. INFER the best approach
- Since we have a slope and one specific point, point-slope form is the most direct method
- We'll use: \(\mathrm{y - y_1 = m(x - x_1)}\), then convert to slope-intercept form
3. TRANSLATE into point-slope form
- Substitute our values: \(\mathrm{y - 1 = -2(x - 3)}\)
4. SIMPLIFY to get slope-intercept form
- Distribute the -2: \(\mathrm{y - 1 = -2x + 6}\)
- Add 1 to both sides: \(\mathrm{y = -2x + 6 + 1}\)
- Combine like terms: \(\mathrm{y = -2x + 7}\)
5. Verify the solution
- Check: When \(\mathrm{x = 3}\), does \(\mathrm{y = 1}\)?
- \(\mathrm{y = -2(3) + 7 = -6 + 7 = 1}\) ✓
Answer: C \(\mathrm{(y = -2x + 7)}\)
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak SIMPLIFY execution: Sign errors when distributing the negative slope through the parentheses.
Students correctly set up \(\mathrm{y - 1 = -2(x - 3)}\) but then make the error: \(\mathrm{y - 1 = -2x - 6}\) (forgetting that \(\mathrm{-2 \times (-3) = +6}\), not -6). This leads to \(\mathrm{y = -2x - 6 + 1 = -2x - 5}\).
This may lead them to select Choice A \(\mathrm{(y = -2x - 5)}\).
Second Most Common Error:
Poor INFER reasoning: Attempting to find the y-intercept directly without using point-slope form.
Students might try to substitute the point \(\mathrm{(3,1)}\) directly into \(\mathrm{y = -2x + b}\) to solve for b, but then make calculation errors like:
\(\mathrm{1 = -2(3) + b}\)
\(\mathrm{1 = -6 + b}\)
\(\mathrm{b = 7}\)
but then mistakenly write \(\mathrm{y = -2x + 1}\).
This may lead them to select Choice B \(\mathrm{(y = -2x + 1)}\).
The Bottom Line:
This problem tests whether students can systematically apply the point-slope form and carefully execute the algebraic steps to convert to slope-intercept form. The key is maintaining accuracy with negative numbers throughout the process.