Three points lie on the same line in the coordinate plane. The coordinates of these points are \((-2, 25)\), \((0,...
GMAT Algebra : (Alg) Questions
Three points lie on the same line in the coordinate plane. The coordinates of these points are \((-2, 25)\), \((0, 15)\), and \((1, 10)\). Which of the following equations represents the line containing these three points?
\(\mathrm{y = -5x + 10}\)
\(\mathrm{y = -5x + 15}\)
\(\mathrm{y = 5x + 10}\)
\(\mathrm{y = 15x - 5}\)
1. TRANSLATE the problem information
- Given information:
- Three points on the same line: \((-2, 25), (0, 15), (1, 10)\)
- Need to find the equation of this line
2. INFER the solution strategy
- To find a linear equation, I need slope (m) and y-intercept (b)
- I can use any two points to find slope with the slope formula
- Since I have the point \((0, 15)\), I can directly identify the y-intercept as 15
3. SIMPLIFY to find the slope
- Using points \((-2, 25)\) and \((0, 15)\):
\(\mathrm{m} = \frac{15 - 25}{0 - (-2)}\)
\(= \frac{-10}{2}\)
\(= -5\)
4. INFER the complete equation
- With slope \(\mathrm{m} = -5\) and y-intercept \(\mathrm{b} = 15\):
\(\mathrm{y} = -5\mathrm{x} + 15\)
5. SIMPLIFY to verify the equation works
- Check \((-2, 25)\):
\(\mathrm{y} = -5(-2) + 15\)
\(= 10 + 15\)
\(= 25\) ✓ - Check \((0, 15)\):
\(\mathrm{y} = -5(0) + 15\)
\(= 0 + 15\)
\(= 15\) ✓ - Check \((1, 10)\):
\(\mathrm{y} = -5(1) + 15\)
\(= -5 + 15\)
\(= 10\) ✓
Answer: B) \(\mathrm{y} = -5\mathrm{x} + 15\)
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak SIMPLIFY skill: Making sign errors when calculating slope, especially with negative coordinates.
Students might calculate:
\(\mathrm{m} = \frac{15 - 25}{0 - (-2)}\)
\(= \frac{-10}{2}\)
\(= 5\) (forgetting the negative)
This leads them to think the equation is \(\mathrm{y} = 5\mathrm{x} + 15\), causing them to select Choice C (\(\mathrm{y} = 5\mathrm{x} + 10\)) after also making an error with the y-intercept.
Second Most Common Error:
Poor INFER reasoning: Not recognizing that the point \((0, 15)\) directly gives the y-intercept.
Students might use a more complicated approach, trying to substitute points into the general form and making algebraic errors in the process. This leads to confusion and potentially selecting Choice A (\(\mathrm{y} = -5\mathrm{x} + 10\)) with the correct slope but wrong y-intercept.
The Bottom Line:
This problem rewards students who recognize the strategic advantage of having a point where \(\mathrm{x} = 0\), allowing them to immediately identify the y-intercept rather than getting bogged down in unnecessary algebra.
\(\mathrm{y = -5x + 10}\)
\(\mathrm{y = -5x + 15}\)
\(\mathrm{y = 5x + 10}\)
\(\mathrm{y = 15x - 5}\)