In the xy-plane, the line y = -3 and the parabola \(\mathrm{y = (x + 4)^2 - 3}\) intersect at...
GMAT Advanced Math : (Adv_Math) Questions
In the xy-plane, the line \(\mathrm{y = -3}\) and the parabola \(\mathrm{y = (x + 4)^2 - 3}\) intersect at exactly one point. What is the x-coordinate of their point of intersection?
Choose 1 answer:
- -7
- -5
- -4
- -3
\(\mathrm{-7}\)
\(\mathrm{-5}\)
\(\mathrm{-4}\)
\(\mathrm{-3}\)
1. TRANSLATE the problem setup
- Given information:
- Line: \(\mathrm{y = -3}\) (horizontal line)
- Parabola: \(\mathrm{y = (x + 4)^2 - 3}\)
- They intersect at exactly one point
- What this tells us: At the intersection point, both curves have the same y-value, so we set the equations equal
2. TRANSLATE into mathematical equation
Set the y-values equal:
\(\mathrm{-3 = (x + 4)^2 - 3}\)
3. SIMPLIFY through algebraic manipulation
- Add 3 to both sides:
\(\mathrm{0 = (x + 4)^2}\)
- INFER the next step: Since \(\mathrm{(x + 4)^2 = 0}\), we take the square root
\(\mathrm{0 = x + 4}\)
- Solve for x:
\(\mathrm{x = -4}\)
4. Verify the solution
Substitute \(\mathrm{x = -4}\) back into the parabola:
\(\mathrm{y = (-4 + 4)^2 - 3}\)
\(\mathrm{= 0^2 - 3}\)
\(\mathrm{= -3}\) ✓
This matches the line \(\mathrm{y = -3}\).
Answer: C. -4
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak TRANSLATE skill: Students may not realize that "intersect" means the y-values must be equal. Instead, they might try to graph both equations or use more complex methods, leading to confusion and potentially guessing among the answer choices.
Second Most Common Error:
Poor SIMPLIFY execution: Students might make sign errors when manipulating the equation, such as forgetting to add 3 to both sides correctly, or making errors when taking the square root. This could lead them to select Choice A (-7) or Choice B (-5) based on calculation mistakes.
The Bottom Line:
This problem tests whether students understand the fundamental concept that intersections occur where curves have equal outputs, combined with solid algebraic manipulation skills. The key insight is recognizing that the setup leads to a perfect square equal to zero.
\(\mathrm{-7}\)
\(\mathrm{-5}\)
\(\mathrm{-4}\)
\(\mathrm{-3}\)