For the linear function g, the graph of \(\mathrm{y = g(x)}\) in the xy-plane has a slope of -5. The...
GMAT Algebra : (Alg) Questions
For the linear function g, the graph of \(\mathrm{y = g(x)}\) in the xy-plane has a slope of -5. The graph of the function has an x-intercept at the point \(\mathrm{(2, 0)}\). Which of the following equations defines g?
\(\mathrm{g(x) = -5x - 10}\)
\(\mathrm{g(x) = -5x + 5}\)
\(\mathrm{g(x) = -5x + 10}\)
\(\mathrm{g(x) = 5x - 10}\)
1. TRANSLATE the problem information
- Given information:
- Slope = -5
- x-intercept at point (2, 0)
- This means we need to find a linear equation where the line has slope -5 and crosses the x-axis at x = 2
2. INFER the solution approach
- Since we know the slope, we can start with slope-intercept form: \(\mathrm{g(x) = mx + b}\)
- We have \(\mathrm{m = -5}\), so \(\mathrm{g(x) = -5x + b}\)
- We need to find the y-intercept (b) using the x-intercept information
3. TRANSLATE the x-intercept into a coordinate point
- x-intercept at \(\mathrm{(2, 0)}\) means: when \(\mathrm{x = 2}\), the function value \(\mathrm{g(2) = 0}\)
- This gives us a point we can substitute into our equation
4. SIMPLIFY to find the y-intercept
- Substitute the point \(\mathrm{(2, 0)}\) into \(\mathrm{g(x) = -5x + b}\):
\(\mathrm{0 = -5(2) + b}\)
\(\mathrm{0 = -10 + b}\)
\(\mathrm{b = 10}\)
5. Write the final equation
- Now we have both \(\mathrm{m = -5}\) and \(\mathrm{b = 10}\)
- Therefore: \(\mathrm{g(x) = -5x + 10}\)
Answer: C
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak TRANSLATE skill: Students confuse x-intercept with y-intercept, thinking the point \(\mathrm{(2, 0)}\) gives them the y-intercept directly as \(\mathrm{b = 0}\).
They might write \(\mathrm{g(x) = -5x + 0 = -5x}\), but this isn't among the choices, leading to confusion and guessing.
Second Most Common Error:
Poor SIMPLIFY execution: Students make sign errors when solving \(\mathrm{0 = -10 + b}\), getting \(\mathrm{b = -10}\) instead of \(\mathrm{b = 10}\).
This leads them to select Choice A (\(\mathrm{g(x) = -5x - 10}\)).
The Bottom Line:
This problem requires students to understand that an x-intercept is a point on the line, not just a number, and that this point can be used to find the missing parameter in the linear equation.
\(\mathrm{g(x) = -5x - 10}\)
\(\mathrm{g(x) = -5x + 5}\)
\(\mathrm{g(x) = -5x + 10}\)
\(\mathrm{g(x) = 5x - 10}\)