A machine's value decreases linearly over time. The table shows the machine's value \(\mathrm{V(t)}\), in thousands of dollars, at time...
GMAT Algebra : (Alg) Questions
A machine's value decreases linearly over time. The table shows the machine's value \(\mathrm{V(t)}\), in thousands of dollars, at time \(\mathrm{t}\) years after purchase.
| \(\mathrm{t}\) | \(\mathrm{V(t)}\) |
|---|---|
| 1 | 47 |
| 3 | 41 |
| 5 | 35 |
Which equation defines \(\mathrm{V(t)}\)?
\(\mathrm{V(t) = -6t + 53}\)
\(\mathrm{V(t) = -3t + 47}\)
\(\mathrm{V(t) = -3t + 50}\)
\(\mathrm{V(t) = 3t + 44}\)
1. TRANSLATE the problem information
- Given information:
- Table showing machine value V(t) in thousands of dollars at time t years
- Values: \(\mathrm{(1, 47), (3, 41), (5, 35)}\)
- Need to find equation in form \(\mathrm{V(t) = mt + b}\)
- What this tells us: We have three coordinate points from a linear relationship
2. INFER the solution strategy
- Since we need a linear equation \(\mathrm{V(t) = mt + b}\), we must find:
- Slope (m) using any two points
- Y-intercept (b) using point-slope form
- Strategy: Calculate slope first, then use point-slope form with one known point
3. SIMPLIFY to find the slope
- Using points \(\mathrm{(1, 47)}\) and \(\mathrm{(3, 41)}\):
- Slope = \(\mathrm{\frac{y_2 - y_1}{x_2 - x_1}}\) = \(\mathrm{\frac{41 - 47}{3 - 1}}\) = \(\mathrm{\frac{-6}{2}}\) = \(\mathrm{-3}\)
4. SIMPLIFY using point-slope form
- Using point \(\mathrm{(1, 47)}\) and slope \(\mathrm{m = -3}\):
- \(\mathrm{V(t) - 47 = -3(t - 1)}\)
- \(\mathrm{V(t) - 47 = -3t + 3}\)
- \(\mathrm{V(t) = -3t + 3 + 47}\)
- \(\mathrm{V(t) = -3t + 50}\)
5. Verify with remaining point
- Check \(\mathrm{(5, 35)}\): \(\mathrm{V(5) = -3(5) + 50 = 35}\) ✓
Answer: C
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak SIMPLIFY skill: Students correctly calculate slope as \(\mathrm{\frac{-6}{2}}\) but fail to simplify to \(\mathrm{-3}\), keeping the slope as \(\mathrm{-6}\) instead.
When they use point-slope form with \(\mathrm{m = -6}\) and point \(\mathrm{(1, 47)}\):
\(\mathrm{V(t) - 47 = -6(t - 1)}\) leads to \(\mathrm{V(t) = -6t + 53}\)
This may lead them to select Choice A \(\mathrm{(-6t + 53)}\)
Second Most Common Error:
Poor SIMPLIFY execution: Students calculate the slope correctly as \(\mathrm{-3}\), but make algebraic errors when converting from point-slope form, particularly forgetting to add the constant terms correctly.
For example, they might get \(\mathrm{V(t) = -3t + 47}\) by not properly distributing or combining terms in the point-slope form.
This may lead them to select Choice B \(\mathrm{(-3t + 47)}\)
The Bottom Line:
This problem tests whether students can systematically work through the two-step process of finding a linear equation: calculating slope accurately and then correctly manipulating the point-slope form. The arithmetic and algebraic precision required in both steps creates multiple opportunities for execution errors.
\(\mathrm{V(t) = -6t + 53}\)
\(\mathrm{V(t) = -3t + 47}\)
\(\mathrm{V(t) = -3t + 50}\)
\(\mathrm{V(t) = 3t + 44}\)