A manager is responsible for ordering supplies for a shaved ice shop. The shop's inventory starts with 4,500 paper cups,...
GMAT Algebra : (Alg) Questions
A manager is responsible for ordering supplies for a shaved ice shop. The shop's inventory starts with \(\mathrm{4,500}\) paper cups, and the manager estimates that \(\mathrm{70}\) of these paper cups are used each day. Based on this estimate, in how many days will the supply of paper cups reach \(\mathrm{1,700}\)?
\(\mathrm{20}\)
\(\mathrm{40}\)
\(\mathrm{60}\)
\(\mathrm{80}\)
1. TRANSLATE the problem information
- Given information:
- Starting inventory: 4,500 paper cups
- Daily usage rate: 70 cups per day
- Target inventory level: 1,700 cups
- Find: Number of days (x) to reach target
2. INFER the mathematical relationship
- Key insight: Remaining inventory decreases linearly over time
- After x days: Remaining = Starting - (Daily rate × Days)
- This gives us: \(4,500 - 70\mathrm{x} = 1,700\)
3. SIMPLIFY by solving the linear equation
- Start with: \(4,500 - 70\mathrm{x} = 1,700\)
\(-70\mathrm{x} = 1,700 - 4,500\)
- Simplify the right side:
\(-70\mathrm{x} = -2,800\)
- Divide both sides by -70:
\(\mathrm{x} = -2,800 ÷ (-70) = 40\)
Answer: B. 40
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak INFER skill: Students may set up the equation incorrectly by adding instead of subtracting daily usage, thinking \(4,500 + 70\mathrm{x} = 1,700\) because they focus on the cups being "used" rather than "remaining."
This backward setup leads to \(-70\mathrm{x} = -2,800\), but then \(\mathrm{x} = -40\), which makes no sense. This leads to confusion and guessing.
Second Most Common Error:
Poor SIMPLIFY execution: Students correctly set up \(4,500 - 70\mathrm{x} = 1,700\) but make arithmetic errors when handling negative numbers, particularly getting confused by \((-2,800) ÷ (-70)\).
Common arithmetic mistakes include getting \(\mathrm{x} = -40\) or \(\mathrm{x} = 2,800/70 ≈ 40\). If they get \(\mathrm{x} = -40\), this may lead them to select Choice A (20) after taking the absolute value.
The Bottom Line:
This problem tests whether students can correctly model a decreasing linear relationship and handle the resulting negative number arithmetic without getting confused.
\(\mathrm{20}\)
\(\mathrm{40}\)
\(\mathrm{60}\)
\(\mathrm{80}\)