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The table summarizes the number of objects in each group.GroupNumber of objectsA375B54C690D81Total1,200The number of objects in group C is p%...

GMAT Problem-Solving and Data Analysis : (PS_DA) Questions

Source: Official
Problem-Solving and Data Analysis
Percentages
MEDIUM
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Notes
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The table summarizes the number of objects in each group.

GroupNumber of objects
A375
B54
C690
D81
Total1,200

The number of objects in group C is \(\mathrm{p}\%\) of the number of objects in group A. What is the value of p?

Enter your answer here
Solution

1. TRANSLATE the problem information

  • Given information:
    • Group A has 375 objects
    • Group C has 690 objects
    • Group C is \(\mathrm{p\%}\) of Group A
  • What this tells us: We need to find what percentage 690 is of 375

2. TRANSLATE the percentage relationship into an equation

  • The phrase "690 is p% of 375" becomes: \(\mathrm{690 = \frac{p}{100} \times 375}\)
  • This is the fundamental percentage equation: \(\mathrm{Part = \frac{Percent}{100} \times Whole}\)

3. SIMPLIFY the equation to solve for p

  • First, multiply out the right side:
    \(\mathrm{690 = \frac{p}{100} \times 375 = 3.75p}\)
  • Now divide both sides by 3.75:
    \(\mathrm{p = 690 \div 3.75}\)
  • Calculate the division (use calculator):
    \(\mathrm{p = 184}\)

Answer: 184




Why Students Usually Falter on This Problem


Most Common Error Path:

Weak TRANSLATE skill: Students confuse which number should be the "whole" and which should be the "part"

They might incorrectly think: "375 is p% of 690" and set up \(\mathrm{375 = \frac{p}{100} \times 690}\), leading to \(\mathrm{p = 375 \div 6.9 \approx 54.3}\). This leads to confusion since 54.3 isn't a clean answer, causing them to abandon systematic solution and guess.


Second Most Common Error:

Poor SIMPLIFY execution: Students make calculation errors when computing \(\mathrm{690 \div 3.75}\)

They might approximate incorrectly (like \(\mathrm{690 \div 4 = 172.5}\)) or make division mistakes, leading to answers that don't match the expected result. This causes them to second-guess their setup and potentially guess randomly.


The Bottom Line:

This problem tests whether students can correctly translate a percentage statement into mathematical form and then execute the arithmetic accurately. The key insight is recognizing that "C is p% of A" means \(\mathrm{C = \frac{p}{100} \times A}\), not the reverse.

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