A number x is at most 17 less than 5 times the value of y. If the value of y...
GMAT Algebra : (Alg) Questions
A number x is at most 17 less than 5 times the value of y. If the value of y is 3, what is the greatest possible value of x?
1. TRANSLATE the problem information
- Given information:
- x is at most 17 less than 5 times the value of y
- \(\mathrm{y = 3}\)
- Need to find the greatest possible value of x
- TRANSLATE the key phrase: "at most 17 less than 5 times y"
- "at most" means \(\leq\)
- "17 less than 5y" means \(\mathrm{5y - 17}\)
- Therefore: \(\mathrm{x \leq 5y - 17}\)
2. SIMPLIFY by substituting the known value
- Substitute \(\mathrm{y = 3}\) into the inequality:
\(\mathrm{x \leq 5(3) - 17}\)
\(\mathrm{x \leq 15 - 17}\)
\(\mathrm{x \leq -2}\)
3. INFER the greatest possible value
- Since \(\mathrm{x \leq -2}\), x can be any value less than or equal to -2
- The greatest value that satisfies this condition is exactly -2
- Values like -1, 0, or 1 would violate the inequality
Answer: -2
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak TRANSLATE skill: Misinterpreting "17 less than 5 times y"
Students often translate this as \(\mathrm{17 - 5y}\) instead of \(\mathrm{5y - 17}\), thinking "17 less than" means "17 minus something." This leads to the inequality \(\mathrm{x \leq 17 - 5y}\). With \(\mathrm{y = 3}\), they get \(\mathrm{x \leq 17 - 15 = 2}\), giving an incorrect greatest value of 2.
Second Most Common Error:
Poor TRANSLATE reasoning: Confusing "at most" with "at least"
Some students translate "at most" as \(\geq\) instead of \(\leq\), creating \(\mathrm{x \geq 5y - 17}\). This gives \(\mathrm{x \geq -2}\), making them think there's no greatest value or that any large positive number works. This leads to confusion and guessing.
The Bottom Line:
Success depends on careful translation of compound phrases. "At most 17 less than 5y" requires parsing two separate pieces: the direction of the inequality ("at most" = \(\leq\)) and the expression being compared to ("17 less than 5y" = \(\mathrm{5y - 17}\)).