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A number x is at most 17 less than 5 times the value of y. If the value of y...

GMAT Algebra : (Alg) Questions

Source: Practice Test
Algebra
Linear inequalities in 1 or 2 variables
MEDIUM
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Notes
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A number x is at most 17 less than 5 times the value of y. If the value of y is 3, what is the greatest possible value of x?

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Solution

1. TRANSLATE the problem information

  • Given information:
    • x is at most 17 less than 5 times the value of y
    • \(\mathrm{y = 3}\)
    • Need to find the greatest possible value of x
  • TRANSLATE the key phrase: "at most 17 less than 5 times y"
    • "at most" means \(\leq\)
    • "17 less than 5y" means \(\mathrm{5y - 17}\)
    • Therefore: \(\mathrm{x \leq 5y - 17}\)

2. SIMPLIFY by substituting the known value

  • Substitute \(\mathrm{y = 3}\) into the inequality:
    \(\mathrm{x \leq 5(3) - 17}\)
    \(\mathrm{x \leq 15 - 17}\)
    \(\mathrm{x \leq -2}\)

3. INFER the greatest possible value

  • Since \(\mathrm{x \leq -2}\), x can be any value less than or equal to -2
  • The greatest value that satisfies this condition is exactly -2
  • Values like -1, 0, or 1 would violate the inequality

Answer: -2




Why Students Usually Falter on This Problem

Most Common Error Path:

Weak TRANSLATE skill: Misinterpreting "17 less than 5 times y"

Students often translate this as \(\mathrm{17 - 5y}\) instead of \(\mathrm{5y - 17}\), thinking "17 less than" means "17 minus something." This leads to the inequality \(\mathrm{x \leq 17 - 5y}\). With \(\mathrm{y = 3}\), they get \(\mathrm{x \leq 17 - 15 = 2}\), giving an incorrect greatest value of 2.

Second Most Common Error:

Poor TRANSLATE reasoning: Confusing "at most" with "at least"

Some students translate "at most" as \(\geq\) instead of \(\leq\), creating \(\mathrm{x \geq 5y - 17}\). This gives \(\mathrm{x \geq -2}\), making them think there's no greatest value or that any large positive number works. This leads to confusion and guessing.

The Bottom Line:

Success depends on careful translation of compound phrases. "At most 17 less than 5y" requires parsing two separate pieces: the direction of the inequality ("at most" = \(\leq\)) and the expression being compared to ("17 less than 5y" = \(\mathrm{5y - 17}\)).

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