For p gt 0, the value q is determined such that p is 125% of q. The function g is...
GMAT Problem-Solving and Data Analysis : (PS_DA) Questions
For \(\mathrm{p \gt 0}\), the value \(\mathrm{q}\) is determined such that \(\mathrm{p}\) is \(125\%\) of \(\mathrm{q}\). The function \(\mathrm{g}\) is defined by \(\mathrm{g(p) = q}\). Which of the following best describes the function \(\mathrm{g}\) for its given domain?
Decreasing exponential
Decreasing linear
Increasing exponential
Increasing linear
1. TRANSLATE the relationship into mathematics
- Given information:
- \(\mathrm{p \gt 0}\) (p is positive)
- "p is 125% of q"
- Function g is defined by \(\mathrm{g(p) = q}\)
- TRANSLATE the key phrase: "p is 125% of q" means \(\mathrm{p = 1.25q}\)
2. INFER what the function definition requires
- The function \(\mathrm{g(p) = q}\) means:
- Input: p
- Output: q
- We need q expressed in terms of p, not the other way around
- Strategy: Solve the equation \(\mathrm{p = 1.25q}\) for q
3. SIMPLIFY to find the function
- From \(\mathrm{p = 1.25q}\), solve for q:
- \(\mathrm{q = p/1.25}\)
- Convert to fraction: \(\mathrm{1.25 = 5/4}\)
- \(\mathrm{q = p ÷ (5/4)}\)
\(\mathrm{= p × (4/5)}\)
\(\mathrm{= 0.8p}\)
- Therefore: \(\mathrm{g(p) = 0.8p}\)
4. INFER the function type and behavior
- The function \(\mathrm{g(p) = 0.8p}\) is in the form \(\mathrm{y = mx}\) where \(\mathrm{m = 0.8}\)
- This is the definition of a linear function
- Since \(\mathrm{m = 0.8 \gt 0}\), the slope is positive
- Positive slope means the function is increasing
Answer: D. Increasing linear
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak TRANSLATE skill: Students may incorrectly interpret "p is 125% of q" as "q is 125% of p," leading to \(\mathrm{q = 1.25p}\) instead of \(\mathrm{p = 1.25q}\).
If they use \(\mathrm{q = 1.25p}\), they get \(\mathrm{g(p) = 1.25p}\), which is still increasing linear, so they might still select the correct answer by accident. However, the more common error is setting up \(\mathrm{q = p/1.25}\) incorrectly as \(\mathrm{q = 1.25/p}\), leading to an inverse relationship.
This may lead them to select Choice A (Decreasing exponential) or Choice B (Decreasing linear).
Second Most Common Error:
Poor INFER reasoning: Students may not recognize that they need to express q in terms of p. They might try to work with \(\mathrm{p = 1.25q}\) directly and get confused about which variable should be the input and which should be the output.
This leads to confusion and guessing among the answer choices.
The Bottom Line:
This problem tests whether students can accurately translate percentage relationships into equations and then manipulate those equations to express functions correctly. The key insight is recognizing that "A is 125% of B" means \(\mathrm{A = 1.25B}\), not \(\mathrm{B = 1.25A}\).
Decreasing exponential
Decreasing linear
Increasing exponential
Increasing linear