The function f is defined by \(\mathrm{f(x) = x^2}\). In the xy-plane, the graph of \(\mathrm{y = f(x)}\) is a...
GMAT Advanced Math : (Adv_Math) Questions
The function f is defined by \(\mathrm{f(x) = x^2}\). In the xy-plane, the graph of \(\mathrm{y = f(x)}\) is a parabola with its vertex at the origin. The graph of \(\mathrm{y = h(x)}\) is a parabola that is the result of shifting the graph of \(\mathrm{y = f(x)}\) so that its vertex is at the point \(\mathrm{(3, -5)}\). Which equation defines the function h?
\(\mathrm{h(x) = (x - 3)^2 - 5}\)
\(\mathrm{h(x) = (x + 3)^2 - 5}\)
\(\mathrm{h(x) = (x - 3)^2 + 5}\)
\(\mathrm{h(x) = (x + 3)^2 + 5}\)
1. TRANSLATE the problem information
- Given information:
- Original function: \(\mathrm{f(x) = x^2}\) with vertex at origin \(\mathrm{(0, 0)}\)
- Transformed function: \(\mathrm{h(x)}\) with vertex at \(\mathrm{(3, -5)}\)
- Need to find the equation for \(\mathrm{h(x)}\)
2. INFER the mathematical approach
- Since we know both the original and new vertex locations, we should use vertex form
- Vertex form: \(\mathrm{y = a(x - h)^2 + k}\), where \(\mathrm{(h, k)}\) is the vertex
- The shape doesn't change, so \(\mathrm{a = 1}\) (same as the original parabola)
3. SIMPLIFY by substituting the vertex coordinates
- From the vertex \(\mathrm{(3, -5)}\): \(\mathrm{h = 3}\) and \(\mathrm{k = -5}\)
- Substitute into vertex form: \(\mathrm{h(x) = 1(x - 3)^2 + (-5)}\)
- Simplify: \(\mathrm{h(x) = (x - 3)^2 - 5}\)
Answer: A
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak TRANSLATE skill: Students misinterpret the direction of horizontal shifts in vertex form. They think moving right 3 units means using \(\mathrm{(x + 3)}\) instead of \(\mathrm{(x - 3)}\).
Their reasoning: "The vertex moved right 3, so I add 3 to x."
This leads them to \(\mathrm{h(x) = (x + 3)^2 - 5}\), causing them to select Choice B.
Second Most Common Error:
Poor SIMPLIFY execution: Students correctly identify vertex form but make sign errors when handling the vertical shift. They write \(\mathrm{h(x) = (x - 3)^2 + 5}\) instead of \(\mathrm{(x - 3)^2 - 5}\).
Their error: Forgetting that \(\mathrm{k = -5}\) means adding (-5), not adding 5.
This may lead them to select Choice C.
The Bottom Line:
Vertex form sign conventions are counterintuitive - rightward shifts use \(\mathrm{(x - h)}\) and downward shifts use \(\mathrm{+k}\) where k is negative. Success requires careful attention to these sign relationships.
\(\mathrm{h(x) = (x - 3)^2 - 5}\)
\(\mathrm{h(x) = (x + 3)^2 - 5}\)
\(\mathrm{h(x) = (x - 3)^2 + 5}\)
\(\mathrm{h(x) = (x + 3)^2 + 5}\)