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In the xy-plane, a parabola has vertex \((-2, 12)\) and intersects the y-axis at \((0, 8)\). If the equation of...

GMAT Advanced Math : (Adv_Math) Questions

Source: Prism
Advanced Math
Nonlinear functions
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In the xy-plane, a parabola has vertex \((-2, 12)\) and intersects the y-axis at \((0, 8)\). If the equation of the parabola is written in the form \(\mathrm{y = ax^2 + bx + c}\), where \(\mathrm{a, b, and c}\) are constants, which of the following could be the value of \(\mathrm{a + b + c}\)?

A

-1

B

3

C

8

D

12

Solution

1. TRANSLATE the problem information

  • Given information:
    • Vertex: \((-2, 12)\)
    • Y-intercept: \((0, 8)\)
    • Need: \(\mathrm{a + b + c}\) where \(\mathrm{y = ax^2 + bx + c}\)

2. INFER the best approach

  • Since we have vertex information, vertex form is most efficient
  • Vertex form: \(\mathrm{y = a(x - h)^2 + k}\) where \((\mathrm{h}, \mathrm{k})\) is the vertex
  • With vertex \((-2, 12)\): \(\mathrm{y = a(x - (-2))^2 + 12 = a(x + 2)^2 + 12}\)

3. TRANSLATE the y-intercept condition

  • Y-intercept \((0, 8)\) means when \(\mathrm{x = 0}\), \(\mathrm{y = 8}\)
  • Substitute into vertex form: \(\mathrm{8 = a(0 + 2)^2 + 12}\)

4. SIMPLIFY to find parameter a

  • \(\mathrm{8 = a(2)^2 + 12}\)
  • \(\mathrm{8 = 4a + 12}\)
  • \(\mathrm{-4 = 4a}\)
  • \(\mathrm{a = -1}\)

5. SIMPLIFY to expand to standard form

  • \(\mathrm{y = -1(x + 2)^2 + 12}\)
  • \(\mathrm{y = -(x^2 + 4x + 4) + 12}\)
  • \(\mathrm{y = -x^2 - 4x - 4 + 12}\)
  • \(\mathrm{y = -x^2 - 4x + 8}\)

6. INFER the final answer

  • From \(\mathrm{y = -x^2 - 4x + 8}\): \(\mathrm{a = -1}\), \(\mathrm{b = -4}\), \(\mathrm{c = 8}\)
  • Therefore: \(\mathrm{a + b + c = -1 + (-4) + 8 = 3}\)

Answer: B. 3


Why Students Usually Falter on This Problem

Most Common Error Path:

Weak INFER skill: Students may try to set up a system of equations using multiple points instead of recognizing that vertex form is the direct path when given vertex information.

They might attempt to find three points and create a system:

  • Use vertex \((-2, 12)\)
  • Use y-intercept \((0, 8)\)
  • Try to find a third point

This leads to unnecessary complexity and potential arithmetic errors, causing confusion and guessing.

Second Most Common Error:

Poor SIMPLIFY execution: Students correctly set up vertex form but make algebraic errors when expanding \(\mathrm{(x + 2)^2}\) or when distributing the negative sign.

Common mistakes:

  • \(\mathrm{(x + 2)^2 = x^2 + 4x + 2}\) (forgetting the constant term is 4, not 2)
  • Incorrect distribution: \(\mathrm{-(x^2 + 4x + 4) = -x^2 - 4x - 4}\) (missing the negative on the constant)

These errors lead to wrong coefficients and thus wrong values for \(\mathrm{a + b + c}\), potentially selecting Choice A (-1) or Choice D (12).

The Bottom Line:

This problem tests whether students can efficiently connect vertex form with standard form. The key insight is recognizing that vertex form provides a direct path to finding the parameter 'a', making the expansion to standard form straightforward.

Answer Choices Explained
A

-1

B

3

C

8

D

12

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