In the xy-plane, a parabola has vertex \((-8, 6)\) and intersects the y-axis at exactly two distinct points. If the...
GMAT Advanced Math : (Adv_Math) Questions
In the xy-plane, a parabola has vertex \((-8, 6)\) and intersects the y-axis at exactly two distinct points. If the equation of the parabola is written in the form \(\mathrm{x = ay^2 + by + c}\), where \(\mathrm{a, b,}\) and \(\mathrm{c}\) are constants, which of the following could be the value of \(\mathrm{a + b + c}\)?
- -17
- -13
- -8
- -5
\(\mathrm{-17}\)
\(\mathrm{-13}\)
\(\mathrm{-8}\)
\(\mathrm{-5}\)
1. TRANSLATE the problem information
- Given information:
- Parabola has vertex \(\mathrm{(-8, 6)}\)
- Equation form: \(\mathrm{x = ay^2 + by + c}\)
- Intersects y-axis at exactly two distinct points
- What this tells us: This is a horizontal parabola (x as a function of y)
2. INFER the approach
- Since we have a horizontal parabola with known vertex, use vertex form first
- The phrase "intersects y-axis at exactly two distinct points" is key - this will create a constraint on our coefficients
- We'll need to expand to standard form, then use the y-axis intersection condition
3. TRANSLATE vertex form to standard form
- Vertex form for horizontal parabola: \(\mathrm{x = a(y - k)^2 + h}\) where \(\mathrm{(h, k)}\) is vertex
- With vertex \(\mathrm{(-8, 6)}\): \(\mathrm{x = a(y - 6)^2 + (-8) = a(y - 6)^2 - 8}\)
4. SIMPLIFY by expanding
- \(\mathrm{x = a(y^2 - 12y + 36) - 8}\)
- \(\mathrm{x = ay^2 - 12ay + 36a - 8}\)
- Comparing with \(\mathrm{x = ay^2 + by + c}\):
- Coefficient of \(\mathrm{y^2}\): \(\mathrm{a = a}\)
- Coefficient of y: \(\mathrm{b = -12a}\)
- Constant term: \(\mathrm{c = 36a - 8}\)
- Therefore: \(\mathrm{a + b + c = a + (-12a) + (36a - 8) = 25a - 8}\)
5. INFER the constraint from y-axis intersection
- "Intersects y-axis at exactly two distinct points" means when \(\mathrm{x = 0}\), we get exactly two different y-values
- Setting \(\mathrm{x = 0}\): \(\mathrm{ay^2 + by + c = 0}\)
- For exactly two distinct real solutions, discriminant must be positive: \(\mathrm{\Delta \gt 0}\)
6. SIMPLIFY the discriminant condition
- \(\mathrm{\Delta = b^2 - 4ac = (-12a)^2 - 4a(36a - 8)}\)
- \(\mathrm{\Delta = 144a^2 - 144a^2 + 32a = 32a}\)
- For \(\mathrm{\Delta \gt 0}\): \(\mathrm{32a \gt 0}\), so \(\mathrm{a \gt 0}\)
7. APPLY CONSTRAINTS to eliminate answer choices
- Since \(\mathrm{a \gt 0}\): \(\mathrm{a + b + c = 25a - 8 \gt -8}\)
- Checking choices:
- (A) \(\mathrm{-17 \lt -8}\) ✗
- (B) \(\mathrm{-13 \lt -8}\) ✗
- (C) \(\mathrm{-8 = -8}\) ✗ (we need \(\mathrm{\gt -8}\))
- (D) \(\mathrm{-5 \gt -8}\) ✓
Answer: D
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak INFER skill: Students don't connect "intersects y-axis at exactly two distinct points" to the discriminant condition. They may correctly expand the vertex form and find \(\mathrm{a + b + c = 25a - 8}\), but then get stuck because they don't realize they need additional constraints to eliminate answer choices. Without the discriminant analysis, all they know is that \(\mathrm{a + b + c = 25a - 8}\) for some value of a, leaving them unable to distinguish between the choices. This leads to confusion and guessing.
Second Most Common Error:
Missing conceptual knowledge: Students may not remember that for a horizontal parabola, the vertex form is \(\mathrm{x = a(y - k)^2 + h}\). Instead, they might try to use the vertical parabola form \(\mathrm{y = a(x - h)^2 + k}\), leading them down a completely wrong path. This conceptual confusion causes them to abandon systematic solution and guess.
The Bottom Line:
This problem requires connecting geometric language ("intersects y-axis at exactly two distinct points") to algebraic conditions (discriminant \(\mathrm{\gt 0}\)). Students who can't make this connection will struggle to find the constraint that makes the problem solvable.
\(\mathrm{-17}\)
\(\mathrm{-13}\)
\(\mathrm{-8}\)
\(\mathrm{-5}\)