The height of a parabolic arch above ground level is modeled by the function \(\mathrm{h(x) = -0.25x^2 + b}\), where...
GMAT Advanced Math : (Adv_Math) Questions
The height of a parabolic arch above ground level is modeled by the function \(\mathrm{h(x) = -0.25x^2 + b}\), where \(\mathrm{x}\) is the horizontal distance in feet from the center of the arch, and \(\mathrm{b}\) is a constant. The function indicates that the arch reaches its maximum height of 144 feet at the center. How far from the center does the arch meet the ground?
\(\mathrm{6}\)
\(\mathrm{12}\)
\(\mathrm{18}\)
\(\mathrm{24}\)
1. TRANSLATE the problem information
- Given information:
- Height function: \(\mathrm{h(x) = -0.25x^2 + b}\)
- x represents horizontal distance from center
- Maximum height is 144 feet at the center
- What this tells us: At \(\mathrm{x = 0}\) (the center), \(\mathrm{h(0) = 144}\)
2. INFER the approach
- Since we know the height at the center, we can find the constant b
- Then we need to find where the arch "meets the ground" - this means where height equals zero
3. SIMPLIFY to find the constant b
- Substitute \(\mathrm{x = 0}\) and \(\mathrm{h(0) = 144}\) into the function:
\(\mathrm{h(0) = -0.25(0)^2 + b}\)
\(\mathrm{b = 144}\) - Our complete function is: \(\mathrm{h(x) = -0.25x^2 + 144}\)
4. TRANSLATE the ground intersection condition
- "Meets the ground" means the height is zero
- Set up the equation: \(\mathrm{h(x) = 0}\)
- This gives us: \(\mathrm{-0.25x^2 + 144 = 0}\)
5. SIMPLIFY the equation
- Add \(\mathrm{0.25x^2}\) to both sides:
\(\mathrm{0.25x^2 = 144}\) - Divide by 0.25:
\(\mathrm{x^2 = 144 \div 0.25 = 576}\) (use calculator) - Take the square root:
\(\mathrm{x = \sqrt{576} = 24}\)
Answer: D. 24
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak TRANSLATE skill: Students may not recognize that "maximum height of 144 feet at the center" means \(\mathrm{h(0) = 144}\). They might try to work with the general form without determining b first, or they might confuse what "at the center" means in terms of the x-coordinate.
This leads to working with an incomplete function and prevents them from setting up the correct equation, causing confusion and guessing.
Second Most Common Error:
Poor SIMPLIFY execution: Students correctly set up \(\mathrm{-0.25x^2 + 144 = 0}\) but make algebraic mistakes. Common errors include forgetting to divide by 0.25 properly (getting \(\mathrm{x^2 = 144}\) instead of \(\mathrm{x^2 = 576}\)) or making arithmetic errors in the division.
This may lead them to select Choice A (6) if they get \(\mathrm{x^2 = 36}\), or Choice B (12) if they get \(\mathrm{x^2 = 144}\).
The Bottom Line:
This problem tests whether students can connect the verbal description of a parabola's vertex to its mathematical representation, then systematically solve for intersection points. Success requires careful translation of language to math and methodical algebraic manipulation.
\(\mathrm{6}\)
\(\mathrm{12}\)
\(\mathrm{18}\)
\(\mathrm{24}\)