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The height of a parabolic arch above ground level is modeled by the function \(\mathrm{h(x) = -0.25x^2 + b}\), where...

GMAT Advanced Math : (Adv_Math) Questions

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Advanced Math
Nonlinear functions
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The height of a parabolic arch above ground level is modeled by the function \(\mathrm{h(x) = -0.25x^2 + b}\), where \(\mathrm{x}\) is the horizontal distance in feet from the center of the arch, and \(\mathrm{b}\) is a constant. The function indicates that the arch reaches its maximum height of 144 feet at the center. How far from the center does the arch meet the ground?

A

\(\mathrm{6}\)

B

\(\mathrm{12}\)

C

\(\mathrm{18}\)

D

\(\mathrm{24}\)

Solution

1. TRANSLATE the problem information

  • Given information:
    • Height function: \(\mathrm{h(x) = -0.25x^2 + b}\)
    • x represents horizontal distance from center
    • Maximum height is 144 feet at the center
  • What this tells us: At \(\mathrm{x = 0}\) (the center), \(\mathrm{h(0) = 144}\)

2. INFER the approach

  • Since we know the height at the center, we can find the constant b
  • Then we need to find where the arch "meets the ground" - this means where height equals zero

3. SIMPLIFY to find the constant b

  • Substitute \(\mathrm{x = 0}\) and \(\mathrm{h(0) = 144}\) into the function:
    \(\mathrm{h(0) = -0.25(0)^2 + b}\)
    \(\mathrm{b = 144}\)
  • Our complete function is: \(\mathrm{h(x) = -0.25x^2 + 144}\)

4. TRANSLATE the ground intersection condition

  • "Meets the ground" means the height is zero
  • Set up the equation: \(\mathrm{h(x) = 0}\)
  • This gives us: \(\mathrm{-0.25x^2 + 144 = 0}\)

5. SIMPLIFY the equation

  • Add \(\mathrm{0.25x^2}\) to both sides:
    \(\mathrm{0.25x^2 = 144}\)
  • Divide by 0.25:
    \(\mathrm{x^2 = 144 \div 0.25 = 576}\) (use calculator)
  • Take the square root:
    \(\mathrm{x = \sqrt{576} = 24}\)

Answer: D. 24


Why Students Usually Falter on This Problem

Most Common Error Path:

Weak TRANSLATE skill: Students may not recognize that "maximum height of 144 feet at the center" means \(\mathrm{h(0) = 144}\). They might try to work with the general form without determining b first, or they might confuse what "at the center" means in terms of the x-coordinate.

This leads to working with an incomplete function and prevents them from setting up the correct equation, causing confusion and guessing.

Second Most Common Error:

Poor SIMPLIFY execution: Students correctly set up \(\mathrm{-0.25x^2 + 144 = 0}\) but make algebraic mistakes. Common errors include forgetting to divide by 0.25 properly (getting \(\mathrm{x^2 = 144}\) instead of \(\mathrm{x^2 = 576}\)) or making arithmetic errors in the division.

This may lead them to select Choice A (6) if they get \(\mathrm{x^2 = 36}\), or Choice B (12) if they get \(\mathrm{x^2 = 144}\).

The Bottom Line:

This problem tests whether students can connect the verbal description of a parabola's vertex to its mathematical representation, then systematically solve for intersection points. Success requires careful translation of language to math and methodical algebraic manipulation.

Answer Choices Explained
A

\(\mathrm{6}\)

B

\(\mathrm{12}\)

C

\(\mathrm{18}\)

D

\(\mathrm{24}\)

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