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In the coordinate plane, vector vec{p} is perpendicular to vector vec{q}. The magnitude of vec{p} is 10sqrt(34) and the magnitude...

GMAT Geometry & Trigonometry : (Geo_Trig) Questions

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Geometry & Trigonometry
Right triangles and trigonometry
HARD
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In the coordinate plane, vector \(\vec{\mathrm{p}}\) is perpendicular to vector \(\vec{\mathrm{q}}\). The magnitude of \(\vec{\mathrm{p}}\) is \(10\sqrt{34}\) and the magnitude of \(\vec{\mathrm{q}}\) is \(24\sqrt{34}\). What is the magnitude of \(\vec{\mathrm{p}} + \vec{\mathrm{q}}\)?

  1. \(14\)
  2. \(26\)
  3. \(14\sqrt{34}\)
  4. \(26\sqrt{34}\)
  5. \(34\sqrt{34}\)
A

\(14\)

B

\(26\)

C

\(14\sqrt{34}\)

D

\(26\sqrt{34}\)

E

\(34\sqrt{34}\)

Solution

1. TRANSLATE the problem information

  • Given information:
    • Vector \(\mathrm{p} \perp \mathrm{q}\) (perpendicular)
    • \(|\mathrm{p}| = 10\sqrt{34}\)
    • \(|\mathrm{q}| = 24\sqrt{34}\)
    • Find: \(|\mathrm{p} + \mathrm{q}|\)

2. INFER the mathematical approach

  • Since the vectors are perpendicular, they form a right angle
  • This means we can use the Pythagorean theorem: \(|\mathrm{p} + \mathrm{q}|^2 = |\mathrm{p}|^2 + |\mathrm{q}|^2\)
  • The sum vector forms the hypotenuse of a right triangle

3. SIMPLIFY by calculating the squares

  • \(|\mathrm{p}|^2 = (10\sqrt{34})^2 = 10^2 \times (\sqrt{34})^2 = 100 \times 34 = 3400\)
  • \(|\mathrm{q}|^2 = (24\sqrt{34})^2 = 24^2 \times (\sqrt{34})^2 = 576 \times 34 = 19584\)

4. SIMPLIFY by adding the squares

  • \(|\mathrm{p} + \mathrm{q}|^2 = 3400 + 19584 = 22984\)
  • Factor out: \(22984 = 676 \times 34\)

5. SIMPLIFY by taking the square root

  • \(|\mathrm{p} + \mathrm{q}| = \sqrt{676 \times 34} = \sqrt{676} \times \sqrt{34} = 26\sqrt{34}\)

Answer: (D) \(26\sqrt{34}\)




Why Students Usually Falter on This Problem

Most Common Error Path:

Weak INFER skill: Not recognizing that perpendicular vectors allow direct application of the Pythagorean theorem

Students might try to add the magnitudes directly:

\(|\mathrm{p} + \mathrm{q}| = |\mathrm{p}| + |\mathrm{q}| = 10\sqrt{34} + 24\sqrt{34} = 34\sqrt{34}\)

This leads them to select Choice (E) \((34\sqrt{34})\)

Second Most Common Error:

Poor SIMPLIFY execution: Making arithmetic errors when working with radical expressions

Students might correctly set up \(|\mathrm{p} + \mathrm{q}|^2 = |\mathrm{p}|^2 + |\mathrm{q}|^2\) but then make calculation errors, such as:

  • Incorrectly squaring: \((10\sqrt{34})^2 = 10\sqrt{34}\) instead of \(100 \times 34\)
  • Forgetting to take the final square root and selecting a choice like \(676 \times 34\)

This leads to confusion and guessing among the remaining choices.

The Bottom Line:

This problem tests whether students can connect the geometric relationship (perpendicular vectors) to the appropriate mathematical tool (Pythagorean theorem) and then execute the algebraic manipulations accurately with radical expressions.

Answer Choices Explained
A

\(14\)

B

\(26\)

C

\(14\sqrt{34}\)

D

\(26\sqrt{34}\)

E

\(34\sqrt{34}\)

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