Point A is located at coordinates \((2, 5)\) and point B is located at coordinates \((14, \mathrm{y})\), where y gt...
GMAT Geometry & Trigonometry : (Geo_Trig) Questions
Point A is located at coordinates \((2, 5)\) and point B is located at coordinates \((14, \mathrm{y})\), where \(\mathrm{y} \gt 5\). The distance from point A to point B is \(13\). What is the value of \(\mathrm{y}\)?
Enter your answer as an integer.
1. TRANSLATE the problem information
- Given information:
- Point A coordinates: \((2, 5)\)
- Point B coordinates: \((14, y)\)
- Distance from A to B: 13
- Constraint: \(\mathrm{y \gt 5}\)
- What this tells us: We need to use the distance formula to create an equation we can solve for y
2. TRANSLATE the distance relationship into an equation
- The distance formula is: \(\mathrm{d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}}\)
- Substituting our values: \(\mathrm{13 = \sqrt{(14-2)^2 + (y-5)^2}}\)
- This gives us: \(\mathrm{13 = \sqrt{144 + (y-5)^2}}\)
3. SIMPLIFY to solve for y
- Square both sides to eliminate the square root: \(\mathrm{169 = 144 + (y-5)^2}\)
- Subtract 144 from both sides: \(\mathrm{25 = (y-5)^2}\)
- Take the square root: \(\mathrm{y-5 = ±5}\)
- This gives us two potential solutions: \(\mathrm{y = 10}\) or \(\mathrm{y = 0}\)
4. APPLY CONSTRAINTS to select the final answer
- Since the problem states \(\mathrm{y \gt 5}\), we must reject \(\mathrm{y = 0}\)
- Therefore: \(\mathrm{y = 10}\)
Answer: 10
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak APPLY CONSTRAINTS reasoning: Students solve the equation correctly but forget to check the constraint \(\mathrm{y \gt 5}\), leading them to consider both \(\mathrm{y = 10}\) and \(\mathrm{y = 0}\) as valid answers. They might arbitrarily pick \(\mathrm{y = 0}\) or get confused about which solution to choose, potentially entering 0 as their final answer.
Second Most Common Error:
Poor SIMPLIFY execution: Students make algebraic errors when squaring both sides or solving \(\mathrm{(y-5)^2 = 25}\). Common mistakes include forgetting that squaring both sides gives 169 (not 13²), or not recognizing that taking the square root of 25 gives ±5. These calculation errors lead to incorrect values that don't satisfy the original equation.
The Bottom Line:
This problem tests whether students can systematically apply the distance formula and carefully work through constraint-based elimination of invalid solutions.