The population of a town is currently 50{,000}, and the population is estimated to increase each year by 3% from...
GMAT Advanced Math : (Adv_Math) Questions
The population of a town is currently \(\mathrm{50{,}000}\), and the population is estimated to increase each year by \(\mathrm{3\%}\) from the previous year. Which of the following equations can be used to estimate the number of years, \(\mathrm{t}\), it will take for the population of the town to reach \(\mathrm{60{,}000}\)?
\(50,000 = 60,000(0.03)^\mathrm{t}\)
\(50,000 = 60,000(3)^\mathrm{t}\)
\(60,000 = 50,000(0.03)^\mathrm{t}\)
\(60,000 = 50,000(1.03)^\mathrm{t}\)
1. TRANSLATE the problem information
- Given information:
- Initial population: 50,000
- Growth rate: 3% increase each year
- Target population: 60,000
- Need to find: equation for number of years (t)
- What "3% increase each year" means: Each year the population becomes \(103\%\) of the previous year
2. INFER how exponential growth works
- With exponential growth, we multiply by the same factor each time period
- A 3% increase means we multiply by \(1.03\) each year (not \(0.03\))
- After t years: Population = \(\mathrm{(Initial)} \times \mathrm{(Growth\ factor)}^\mathrm{t}\)
3. TRANSLATE this into our specific equation
- Starting population: 50,000
- Growth factor: \(1.03\)
- After t years: \(50,000(1.03)^\mathrm{t}\)
- We want this to equal 60,000
4. Set up the final equation
- Target population = Initial population × \(\mathrm{(Growth\ factor)}^\mathrm{t}\)
- \(60,000 = 50,000(1.03)^\mathrm{t}\)
Answer: D
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak TRANSLATE skill: Students see "3% increase" and immediately think to use \(0.03\) as the multiplier, forgetting that a 3% increase means the new amount is \(103\%\) of the original.
With this error, they might choose Choice C (\(60,000 = 50,000(0.03)^\mathrm{t}\)), not realizing that multiplying by \(0.03\) would actually cause the population to decrease dramatically each year, not increase.
Second Most Common Error:
Poor INFER reasoning about equation setup: Students might set up the equation backwards, thinking the current population should equal some expression involving the target population.
This leads them to select Choice A (\(50,000 = 60,000(0.03)^\mathrm{t}\)) or Choice B (\(50,000 = 60,000(3)^\mathrm{t}\)), neither of which makes logical sense since the smaller current population cannot equal an expression starting with the larger target population.
The Bottom Line:
The key insight is recognizing that "3% increase" means multiplying by \(1.03\) (which is \(100\% + 3\%\)), not by \(0.03\). This fundamental translation error leads to most wrong answers on exponential growth problems.
\(50,000 = 60,000(0.03)^\mathrm{t}\)
\(50,000 = 60,000(3)^\mathrm{t}\)
\(60,000 = 50,000(0.03)^\mathrm{t}\)
\(60,000 = 50,000(1.03)^\mathrm{t}\)